How to compare floating point numbers in shell script?


 
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# 8  
Old 11-28-2009
Hi, what do you mean? Would this ksh93 code be floating pointy enough?
Code:
if [[ 1.999999999998 -gt 1.9999999999799 ]] ; then
  echo hallo
fi

Code:
if [[ 1.999999999998 -lt 1.9999999999799 ]] ; then 
  echo hallo
fi

# 9  
Old 11-28-2009
What scrutinizer wrote DOES work - but in ksh93.

ghostdog gave you a link to CFA Johnson's post - which gives you an awk answer, or tells you to use bc to multiply to force the values into integers.

Modern shells (ksh88 and bash) do NOT support floating point. Period. And the integers are limited to a range of (this is shown as C constants)
#define LONG_MAX 2147483647
#define LONG_MIN (-2147483647 - 1)

If the number you create by multiplication exceeds LONG_MAX/LONG_MIN you then have to use awk.

End of story in SHELL.

If you don't like this, then write some C/perl/python/ruby code that takes two floating point arguments and compares them

Last edited by jim mcnamara; 11-28-2009 at 09:18 AM..
# 10  
Old 11-28-2009
An old post with one solution: https://www.unix.com/52358-post10.html
# 11  
Old 11-29-2009
Quote:
Modern shells (ksh88 and bash)
Actually ksh88 is not a modern shell and should be replaced with ksh93. Similar with pdksh, the public domain clone of ksh88.

Another shell that has good floating point support is zsh.
# 12  
Old 11-30-2009
I think it work for floating point but you must use in korn shell only



a=12.345
b=12.354

if [ "$(echo "if (${a} >= ${b}) 1" | bc)" -eq 1 ]
then
echo "more"
else
echo "less"
fi
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