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Shell Programming and Scripting

Output formatting help needed.

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# 1  
Old 11-03-2009
Output formatting help needed.
Hi guys ,
I have a file which contains following string.(filename tempdisplay)
(location 0.0.0.0:5900)

i needed to write a script which will extract the string that comes after
0.0.0.0 i.e the string :5900.

I have used following method to extract the string :5900 .Is it a preferred way of doing the job as following script will create two files?

Code:
sed s/"(location 0.0.0.0"/""/ tempdisplay > temp2display
#temp2display will now contain :5900)
temp=`sed s/")"/""/ temp2display`
#temp will now contain :5900
echo $temp

output:
:5900
Last edited by pludi; 11-03-2009 at 04:16 AM.. Reason: code tags, please...
# 2  
Old 11-03-2009
Assuming :5900 is the required output:

Code:
echo "(location 0.0.0.0:5900)" | sed 's/^.\+\(:[0-9]\+\))/\1/'

# 3  
Old 11-03-2009
Some more options:
Code:
grep -o ':[0-9]*' tempdisplay

Code:
grep -o ':[^)]*' tempdisplay

Code:
IFS=: read x temp <tempdisplay
echo :${temp%?}

Code:
IFS=":)" read x temp <tempdisplay
echo :$temp

# 4  
Old 11-03-2009
Quote:
Originally Posted by ripat
Assuming :5900 is the required output:

Code:
echo "(location 0.0.0.0:5900)" | sed 's/^.\+\(:[0-9]\+\))/\1/'

Can u please explain the logic behind the query.
# 5  
Old 11-03-2009
Code:
$ echo "(location 0.0.0.0:5900)"  |awk -F[:\)] '{print $2}'
5900

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