Sh programming


 
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# 1  
Old 10-29-2009
Sh programming

I have started writing one script. It is not taking the if block.

Here is the script:
Code:
#!/bin/sh
set USER='/usr/ucb/whoami'
 
#######################################################################
#Killing Process
#######################################################################
echo "$USER"
if ("$USER"=="akaur1")
then 
echo 'killing process' >> /apps/jate/qisscript.log
#elif ( "$USER" == "qisadmin") 
#then
#sudo /etc/init.d/jatedaemon.sh stop

fi


When I run this, it is displaying akaur1 at starting, but after that it is giving: TEST_SCRIPT.sh: akaur1: not found



Please help

Last edited by pludi; 10-29-2009 at 07:51 AM.. Reason: code tags, please...
# 2  
Old 10-29-2009
something like this :
Code:
if [ $user == "akura1" ];
then
.........
else
........
fi

# 3  
Old 10-29-2009
Still same error:
TEST_SCRIPT.sh: [akaur1==akaur1]: not found
# 4  
Old 10-29-2009
You need a space after [ and before ].
# 5  
Old 10-29-2009
I put a space before and after, now its giving,
TEST_SCRIPT.sh: [akaur1: not found
# 6  
Old 10-29-2009
Quote:
Originally Posted by panyam
something like this :
Code:
if [ $user == "akura1" ];
then
.........
else
........
fi

Sorry , it should be :
Code:
if [ $user = "akura1" ];
then
.........
else
........
fi

# 7  
Old 10-29-2009
Hi,

Pleas chk it out. and you have use single "=" only.
Code:
#!/bin/sh
set USER=`/usr/ucb/whoami`

#######################################################################
#Killing Process
#######################################################################
echo "$USER"
if [ "$USER" = "akaur1" ]
then 
echo 'killing process' >> /apps/jate/qisscript.log
#elif ( "$USER" == "qisadmin") 
#then
#sudo /etc/init.d/jatedaemon.sh stop
fi


Last edited by pludi; 10-29-2009 at 08:01 AM.. Reason: code tags, please...
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