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# 8  
Old 10-27-2009
use either nawk or /usr/xpg4/bin/awk if on Solaris
# 9  
Old 10-27-2009
Code:
$ cat FILE1.TXT
2293847982374 sdj 23423
2298372038974 dsj 23492
2972837629376 abj 34929
2984836398384 abc 39723

$ cat ./add_trailer.ksh
#!/bin/ksh
MYFILE=FILE1.TXT
FILECOUNT=$(wc -l < $MYFILE 2>/dev/null)
typeset -Z6 TRAILER=${FILECOUNT:-0}
echo "3$TRAILER" >> $MYFILE
exit 0

$ ./add_trailer.ksh

$ cat FILE1.TXT
2293847982374 sdj 23423
2298372038974 dsj 23492
2972837629376 abj 34929
2984836398384 abc 39723
3000004

# 10  
Old 10-27-2009
Quote:
Originally Posted by vgersh99
use either nawk or /usr/xpg4/bin/awk if on Solaris
thanks it works..

I also like to know i am getting some value into a variable using grep command
Code:
count_trlr=`grep "^3" $DATADIR/$FILE1.DAT| cut -c2-8`

After i get the value into variable i want to remove zeroes
eg: count_trlr=000004 but i want only the number 4 not zeroes like this, count_trlr=4

Code:
 
eg:
contr_trlr=0023343, i want 23343
contr_trlr=1111111, i want 1111111
contr_trlr=0222222, i want only 222222

how to do this in ksh script.

thanks in adv.
# 11  
Old 10-27-2009
Code:
#!/bin/ksh

typeset -i count_trlr=$(grep "^3" $DATADIR/$FILE1.DAT| cut -c2-8)

# 12  
Old 10-27-2009
Code:
$ contr_trlr=0023343
$ echo  $contr_trlr|tr -d '^0'
23343

$ contr_trlr=1111111
$ echo  $contr_trlr|tr -d '^0'
1111111

$ contr_trlr=0222222
$ echo  $contr_trlr|tr -d '^0'
222222


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