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Display LineNo Incase Total Number Of Delimiter Does matches in a given variable

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# 1  
Old 10-23-2009
Display LineNo Incase Total Number Of Delimiter Does Not Not matches in a given variable

I have many files .dat extension.

requirement is to display line no
if no of delimiter does not matches in a given variable

lets say

File: REF_BETOS.dat



Output should display the filename and lineno

your help is appreciated

I am trying with statment
awk -F"$Delimiter" '{print NR NF-1}';

OutPut should look like

File Name Line No

Last edited by ainuddin; 10-23-2009 at 11:29 AM.. Reason: Thread tital should be "Delimiter Does Not matches"
# 2  
Old 10-23-2009
awk -F'~' -v nd="$Delimiter" 'NF!=nd+1{print FILENAME, FNR}' *.dat

Hope it's not a homework assignment.

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