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Count the decimal numbers with 6 precision


 
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# 1  
Old 10-21-2009
Count the decimal numbers with 6 precision

Hi guys,

I have a single column file with millions of records. I want to count the number of records with 6 decimal precision.

for ex:

1234.12
1234.132
12345.12345
1234.1
1234.13
1234.123456
243435.454555


i need to count the number of records with precision of 6 ( i.e here the count is 2)

Any kind of help is appreciated

THanks!
Marcus
# 2  
Old 10-21-2009
Code:
nawk -F. '{if (length($2)==6) s++}END{print s}'  myFile

This User Gave Thanks to vgersh99 For This Post:
# 3  
Old 10-21-2009
Thanks! vgersh99, i will try that out and will let you know about the result.


Thanks!
# 4  
Old 10-21-2009
Code:
grep -c '\.[0-9]\{6\} *$' infile

# 5  
Old 10-21-2009
(g)awk
Code:
awk -F. 'length($2)==6{t++}END{print t}' file

This User Gave Thanks to ghostdog74 For This Post:

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