Shell Programming and Scripting

Actually I got a list of file end with *.txt
I want to use the same command apply to all the *.txt
Thus I try to find out the fastest way to write those same command in a script and then want to let them run automatics.

For example:
I got the file below:
file1.txt
file2.txt
file3.txt
file4.txt

I want all the *.txt do the same command like:
awk '{print $1"\t"}'

My desired output is got a script named as txt.sh look like this:
awk '{print $1"\t"}' file1.txt
awk '{print $1"\t"}' file2.txt
awk '{print $1"\t"}' file3.txt
awk '{print $1"\t"}' file4.txt

The way I do now is :
ls *.txt | awk '{print "awk \"{$_\"\\t\"}\"",$1}'

And the output I get is like this:
awk "{print $1"\t"}" file1.txt
awk "{print $1"\t"}" file2.txt
awk "{print $1"\t"}" file3.txt
awk "{print $1"\t"}" file4.txt

If I type something like:
ls *.txt | awk '{print "awk \'{$_\"\\t\"}\'",$1}'
It is not worked at all.

Thus I'm asking whether you know the way to express the single quote by awk print to get my desired output result
thanks again for all of your suggestion

Why would you want to make and execute txt.sh when

Code:

awk '{print $1"\t"}' `ls *.txt`

will do the same thing without all the system overhead?

Try this:

Code:

awk '{print "awk \047{print $1 \042\\t\042}\047 " $0}' file

My output:

Code:

$ cat file
file1.txt
file2.txt
file3.txt
file4.txt
$
$ awk '{print "awk \047{print $1 \042\\t\042}\047 " $0}' file
awk '{print $1 "\t"}' file1.txt
awk '{print $1 "\t"}' file2.txt
awk '{print $1 "\t"}' file3.txt
awk '{print $1 "\t"}' file4.txt
$

That command will fail if any of the filenames contain embedded newlines or other "pathological" characters.

And the ls command and the sub-shell are unnecessary anyway.

Use shell globbing instead:

Code:

awk '{ print $1 "\t" }' *.txt

You're absolutely on target, Radoulov. Keeping sharp by peer review is why I'm here. Thanks!