how to validate a field when it is blank using awk prog

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# 15  
Old 09-29-2009
Glad to hear that you solved it yourself. May I suggest some optimization for your code?

Parsing fixed length records is easy with GNU awk. Working on the sample file you gave above:
0000000200aaaaaa aaaaaaaa aaaaaaaaa 00/00/00 00:00:00000000 1 1111111 2222.22 2222.22 00

With GNU awk, it is as easy as this:
    FIELDWIDTHS="1 1 1 5 2 26 17 7 2 8 8 7 1 2 2"
    for (i=1;i<=NF;i++){
        printf "Field%d:: %s\n", i, $i

With original awk or nawk, you need to create your own parse function:
function mysplit(str, width){
    str=substr(str, offset, width)
    return str

    n=split(fieldwidths, a, "_")
    for (i=1;i<=n;i++){
        printf "Field%d:: %s\n", i, mysplit($0,a[i])

Both snippets will yield:
Field1:: 0
Field2:: 0
Field3:: 0
Field4:: 00002
Field5:: 00
Field6:: aaaaaa aaaaaaaa aaaaaaaaa 
Field7:: 00/00/00 00:00:00
Field8:: 000000 
Field9:: 1 
Field10:: 1111111 
Field11:: 2222.22 
Field12:: 2222.22
Field14:: 00

When you define the fieldwidths values, don't forget to include the spaces.
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