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Top Forums Shell Programming and Scripting help with file formatting
# 8  
Old 09-18-2009
Code:
 nawk 'BEGIN{FS=RS="";OFS=","} $1=$1' myFile



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# 9  
Old 09-18-2009
The solution of vidyadhar85 gives:

Code:
$ awk 'ORS=(NF)?",":"\n"' file
AAA,pqr,jkl,mnop,abcd,
BBB,abc,pqrs,xyz,uvw,,efgh,uvw,,rpk,
CCC,123,456,789,$

The solution of summer_cherry gives:

Code:
$ sed -n '/^$/!{
      $!{H;}
      ${H;x;s/\n/,/2;s/\n//g;p;}
      }
    /^$/{x;s/\n/,/2;s/\n//g;p;}' file
AAA,pqr,jkl,mnop,abcd
BBB,abc,pqrs,xyz,uvw,efgh,uvw,rpk
CCC,123,456,789
$

The solution of radoulov gives:

Code:
$ awk -F, 'END { print r }
NR > 1 && /[A-Z]/ {
  print r; r = ""
  }
{ r = r ? r $0 : $0 FS }
' file
AAA,
pqr,jkl,mnop,abcd,
BBB,
abc,pqrs,xyz,uvw,,
efgh,uvw,,
rpk,
CCC,123,456,789
$

The solution of vgersh99 gives:

Code:
$ nawk 'BEGIN{FS=RS="";OFS=","} $1=$1' file
A,A,A,
,p,q,r,,,j,k,l,,,m,n,o,p,,,a,b,c,d
B,B,B,
,a,b,c,,,p,q,r,s,,,x,y,z,,,u,v,w,,,
,e,f,g,h,,,u,v,w,,,
,r,p,k
C,C,C,
,1,2,3,,,4,5,6,,,7,8,9
$


The expected output is:

Code:
AAA,pqr,jkl,mnop,abcd
BBB,abc,pqrs,xyz,uvw,efgh,uvw,rpk
CCC,123,456,789

Only the solution of summer_cherry gives me the right output. Am I missing something?

My approach:

Code:
awk '{$1=$1;gsub(",,",",")}1' OFS="," RS="\n\n" file

Output:

Code:
$ awk '{$1=$1;gsub(",,",",")}1' OFS="," RS="\n\n" file
AAA,pqr,jkl,mnop,abcd
BBB,abc,pqrs,xyz,uvw,efgh,uvw,rpk
CCC,123,456,789
$

Regards
# 10  
Old 09-18-2009
I get the following output:
Code:
$ nawk 'BEGIN{FS=RS="";OFS=","} $1=$1' pr.txt
AAA,pqr,jkl,mnop,abcd
BBB,abc,pqrs,xyz,uvw,,efgh,uvw,,rpk
CCC,123,456,789

Sure, not exactly what the OP wanted. Here's another version:
Code:
nawk 'BEGIN{FS=RS="";OFS=","} {for(i=1;i<=NF;i++) sub(",$", "", $i)}$1=$1' pr.txt
AAA,pqr,jkl,mnop,abcd
BBB,abc,pqrs,xyz,uvw,efgh,uvw,rpk
CCC,123,456,789

Franklin52, the potential issue with your code is that you assume that there're no embedded 'empty' fields in any of the lines: ',,':
Code:
BBB
abc,pqrs,,xyz,uvw,
efgh,,uvw,
rpk

# 11  
Old 09-18-2009
Franklin52's post is important. What version of awk using my code produces the output you mentioned?

Code:
% nawk --version
awk version 20070501
% nawk -F, 'END { print r }
NR > 1 && /[A-Z]/ {
  print r; r = ""
  }
{ r = r ? r $0 : $0 FS }
' infile        
AAA,pqr,jkl,mnop,abcd
BBB,abc,pqrs,xyz,uvw,efgh,uvw,rpk
CCC,123,456,789
% gawk --version |head -1
GNU Awk 3.1.7
% gawk -F, 'END { print r }
NR > 1 && /[A-Z]/ {
  print r; r = ""
  }
{ r = r ? r $0 : $0 FS }
' infile        
AAA,pqr,jkl,mnop,abcd
BBB,abc,pqrs,xyz,uvw,efgh,uvw,rpk
CCC,123,456,789

On Solaris:

Code:
$ nawk -F, 'END { print r }
> NR > 1 && /[A-Z]/ {
>   print r; r = ""
>   }
> { r = r ? r $0 : $0 FS }
> ' infile
AAA,pqr,jkl,mnop,abcd
BBB,abc,pqrs,xyz,uvw,efgh,uvw,rpk
CCC,123,456,789
$ /usr/xpg4/bin/awk -F, 'END { print r }
NR > 1 && /[A-Z]/ {
  print r; r = ""
  }
{ r = r ? r $0 : $0 FS }
' infile
AAA,pqr,jkl,mnop,abcd
BBB,abc,pqrs,xyz,uvw,efgh,uvw,rpk
CCC,123,456,789

Input file used:

Code:
AAA
pqr,jkl,mnop,abcd

BBB
abc,pqrs,xyz,uvw,
efgh,uvw,
rpk

CCC
123,456,789



---------- Post updated at 02:56 PM ---------- Previous update was at 02:53 PM ----------

Franklin52's code assumes an awk implementation that supports multi character record separator (RS). So it will work only with GNU awk or tawk (?) I suppose.

---------- Post updated at 02:59 PM ---------- Previous update was at 02:56 PM ----------

Franklin52 , could you please post the sample data used in your examples? Is it different from the OP example?

---------- Post updated at 03:09 PM ---------- Previous update was at 02:59 PM ----------

vgersh99's solutions are old nawk specific, because setting FS to an empty string has a different meaning in the other awk implementations (not sure about mawk and tawk, though).
# 12  
Old 09-18-2009
Strange, I am using GNU Awk 3.1.5 and I use the same input file as the OP.... Smilie.

Regards
# 13  
Old 09-18-2009
Quote:
Originally Posted by Franklin52
Strange, I am using GNU Awk 3.1.5 and I use the same input file as the OP.... Smilie.

Regards
Thank you very much for the info. It's because of the locale (you're using UTF-8 or similar) Smilie
The correct command should be:

Code:
LANG=C awk -F, 'END { print r }
NR > 1 && /[A-Z]/ { 
  print r; r = "" 
  }
{ r = r ? r $0 : $0 FS }
' infile

The problematic part is [A-Z].

---------- Post updated at 03:30 PM ---------- Previous update was at 03:27 PM ----------

Another workaround is to use [[:upper:]] (if supported) instead of [A-Z].
# 14  
Old 09-18-2009
Only summer_cherry and radoulov solution work as expected on my OS.
Code:
# /usr/bin/awk --version
awk version 20070501 (FreeBSD)


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