Shell Programming and Scripting

Hi All,

I have a CSV file in which some fields contains special character for ex:-

my file is file 1

Code:

cat file1
abcd,bgfht,ngbht,abvc ****
hdlld,hsgdt,bhfy,knht ****

whenever i am trying to put a 4th feild in a variable its giving me list of all the files i have in current directory like:-

Code:

cat file1|while read line
do
 
VARIABLE=`echo $line|awk -F "," '{print $4}'`
done

instead of giving abvc **** and knht **** in a variable its giving me
abvc file1 file2 file3...etc all the files which i have in my directory.


Please suggest.

Regards,
SAM

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---------- Post updated at 17:34 ---------- Previous update was at 17:30 ----------

use something like this:

Code:

while read line
do
 
VARIABLE=$(awk -F "," '{print $4}' $line)
done << file1

This is not working..

No value coming to Vriable.

i haven't told that this IS working... i haven't checked the code only the "while read ..." construct. just do a "set -xv" in your code and debug it at runtime... i'm not familar with awk, so there can be the problem...

Hi sam:

My understanding on your question is
you want to display the 4th column in that file if that was your ques then

awk '{print $4}' <filename>

the above code will work...
am sorry if i hav mistook your ques

---------- Post updated at 10:12 PM ---------- Previous update was at 10:05 PM ----------

sam:

my understanding about ur problem could be your $line is not given within quotes...
modified code should be
VARIABLE=`echo "$line"|awk -F "," '{print $4}'`
let us know if it works

Regards,
Vivek

Code:

cat file1|while read line
do
        VARIABLE=`echo "${line}"|awk -F\, '{print $4}'`
        echo "${VARIABLE}"
done

./scriptname

abvc ****
knht ****

it is working thanx know d unknown