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awk comparison with variable


 
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# 1  
Old 09-07-2009
awk comparison with variable

hi,

I want to compare i variable in the awk statement but its not working out. Pl help me out

If we do the comparison like this its OK,

Code:
cat sample | awk -F" ", '{if ($1=="1-Sep-2009") print $1,$2,$3,$4,$5}'


But if u use a variable instead of "1-Sept-2009", it does not return anything,

Code:
d1=$(TZ=GMT-24 date +%cc | awk -F" ", '{print $1}')
d1=$(TZ=GMT-24 date +%cc | awk -F" ", '{print $2}')
cat sample | awk -F" ", '{if ($1==($d1"-"$d2"-2009") print $1,$2,$3,$4,$5}'


Pl suggest how can i incorporate this?

Thanks

Last edited by vgersh99; 09-07-2009 at 05:39 PM.. Reason: code tags, PLEASE!
# 2  
Old 09-07-2009
Hello,

Check this User guide:
The GNU Awk User's Guide

Translated for your problem:
Code:
awk -F" " -v d1="$d1" -v d2="$d2" '$1==d1"-"d2"-2009" {print $1,$2,$3,$4,$5}'

# 3  
Old 09-07-2009
To keep the forums high quality for all users, please take the time to format your posts correctly.

First of all, use Code Tags when you post any code or data samples so others can easily read your code. You can easily do this by highlighting your code and then clicking on the # in the editing menu. (You can also type code tags [code] and [/code] by hand.)

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