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Create a script which sorts a file


 
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# 1  
Old 08-31-2009
Create a script which sorts a file

I have a file below which has a list of users and roles with each row having unique combination of users and roles.

USER1 ROLE1
USER1 ROLE2
USER2
USER3 ROLE1
USER3 ROLE2
USER3 ROLE3
USER4 ROLE2
....
....


I am trying to create a script which sorts the above file to have all the roles in one line delimited by commas per user to look like below:

USER1 ROLE1,ROLE2
USER2
USER3 ROLE1,ROLE2,ROLE3
USER4 ROLE2
....
....


I was able to do this with the script below but when the input is very large it takes very long and takes up cpu usage so I was wondering if someone could tell me a faster way to achive this.


Code:
#!/bin/ksh

INPUT=$1

cut -d' ' -f1 $INPUT | sort -u > USER_LIST

while read USER
do
**** ROLES=$(echo "`grep $USER $INPUT | cut -d' ' -f2 | tr '\12' ','`" | sed -e
's/,$//g')

**** [[ $USER != $ROLES ]] && echo $USER $ROLES
**** [[ $USER = $ROLES ]] && echo $USER

done < USER_LIST


Last edited by Neo; 08-31-2009 at 05:47 AM.. Reason: code tags.
# 2  
Old 08-31-2009
Hello,

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The UNIX and Linux Forums
# 3  
Old 08-31-2009
Something like this :

Code:
awk '{ a[$1]=a[$1]$2"," ;next } END {for ( i in a) {print i" "a[i] }}' File_name |sed 's/,$//'


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