and want to count the number of dots in the first field to find out the level of the section.
I use the gsub function for the job, which works if I pass the pattern directly.
The awk program
Code:
/.*/ {
count = gsub(/\./, "&", $1)
print count
}
correctly prints out the number of dots, output of the first four lines (see sample file above) is
Code:
0
1
1
2
If I try to store the dot-pattern in a variable things mess up. The program
Hello,
We have wrote shell script for multiple file name search pattern.
file format: <numner>_<20180809>.txt
starting with single number and ending with 8 digits number
Command:
awk -v string="12_1234" -v serch="^+_+$" "BEGIN{ if (string ~/serch$/) print string }"
If sting matches... (4 Replies)
The bash bash below extracts the oldest folder from a directory and stores it in filename
That result will match a line in bold in input. In the matching line there is an_xxx digit in italics that
(once the leading zero is removed) will match a line in link. That is the lint to print in output.... (2 Replies)
Greetings Experts,
As part of automating the sql generation, I have the source table name, target table name, join condition stored in a file join_conditions.txt which is a delimited file (I can edit the file if for any reason). The reason I needed to store is I have built SELECT list without... (5 Replies)
hi,
i have a variable which contains some file names delimited by a single space.
FNAME="s1.txt s2.lst s3.cvs s4.lst"
i have another variable that contains a pattern
FILE_PATTERN="*.lst"
i want to take the filenames from FNAME variable and assign each file name in to an array say
for... (8 Replies)
Hello;
I have:
ll | grep -v ^d | awk '{print $9}'
rcx_access_report_fid.txt
rcx_access_report_hsi.txt
rcx_access_report_mmm.txt
rcx_access_report_qsc.txt
I want to get:
rcx_access_report_fid.txt
rcx_access_report_hsi
rcx_access_report_mmm
rcx_access_report_qsc
But when I try: (9 Replies)
Hi everyone,
Can anyone tell me how to take contents of a variable as a pattern for awk command. Am doing as below, but doesnt get any output:
$c = "Tue Dec";
$log = ` awk '/ \$c /' in.txt`;
print $log; (7 Replies)
I have two variables,
my $filename = "abc_yyyy_mm_dd.txt";
my $filename1 = " abc_2011_11_07.txt";
I need to perform some operations after checking if $filename has $filename1 in it
i have used the below code,
if($filename =~ /^$filename1/)
{
----
--
} (2 Replies)
can anyone please help me with this:
i have written a shell script and a stored procedure which has one OUT parameter. now i want to use that out parameter as an input to the unix script but i am getting an error as variable not found. below are the unix scripts and stored procedure...
... (4 Replies)
Dear all,
¿How can i insert a variable in a AWK pattern?
I have almost succeeded in solving a puzzle with AWK but now i want to make a script. Let me explain.
cat file.txt | awk 'BEGIN {RS="\\n\\n"} /tux/ { print "\n"$0 }'
I know that this command makes right what i want to do, but mi... (8 Replies)
Hi all,
I have a variable say var1 (output from somewhere, which I can't change)which store something like this:
echo $var1
name=fred
age=25
address="123 abc"
password=pass1234
how can I make the variable $name, $age, $address and $password contain the info?
I mean do this in a... (1 Reply)