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cat $como_file | awk /^~/'{print $1","$2","$3","$4}' | sed -e 's/~//g'

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Top Forums Shell Programming and Scripting cat $como_file | awk /^~/'{print $1","$2","$3","$4}' | sed -e 's/~//g'
# 1  
Old 08-25-2009
cat $como_file | awk /^~/'{print $1","$2","$3","$4}' | sed -e 's/~//g'
hi All,

Code:
 
cat file_name | awk /^~/'{print $1","$2","$3","$4}' | sed -e 's/~//g'

Can this be done by using sed or awk alone
# 2  
Old 08-25-2009
For a simliar thread I replied. Was that not working after I gave corrected solution?

---------- Post updated at 08:09 PM ---------- Previous update was at 08:08 PM ----------

https://www.unix.com/shell-programmin...#post302347286
# 3  
Old 08-25-2009
Hi rakesh this is differen one.. but looks same....
# 4  
Old 08-25-2009
I know, you should have tried after seeing the previous solution.
Try:

Code:
awk '/^~/ {gsub(/~/,"",$1); gsub(/~/,"",$2); gsub(/~/,"",$3); gsub(/~/,"",$4); print $1","$2","$3","$4}' b

If you are certain there are only 4 fields then you can do it using $0...
# 5  
Old 08-25-2009
gsub is not there...
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