[bash] Manipulate dir name

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# 1  
Old 08-18-2009
[bash] Manipulate dir name


as output i get a directory (i don't know its name) with many files inside.
Now i need to find the directory name and change it as i need.

I can found a directory name with this command:

find -maxdepth 1 -type d | grep out

Now i'd like to assign it to a variable and change it.
for example (i know that's not correct) something like:

if the directory name is "dir.out"
name=find -maxdepth 1 -type d | grep out

#now name=dir.out and i change it as a string

#now name should be name=kir.out

Can anyone suggest a solution


# 2  
Old 08-18-2009
What do you know about the directory that is created?

- Is it always in the same root directory?
- Does it always contain a file name that you can predict?
- Is it owned by a unique user or group?
# 3  
Old 08-18-2009

thanks for reply.

about your questions
- Is it always in the same root directory?
- Does it always contain a file name that you can predict?
- Is it owned by a unique user or group?
The directory change accordly the date and time .
Yes is always in the same directory.
I can control the permits and who owned the dir.

I'm trying to solve the problem also with python.

# 4  
Old 08-18-2009
Before advancing into variables, can you run the command below to achieve your expected result?

mv `find -maxdepth 1 -type d | grep out` kir.out

# 5  
Old 08-18-2009
I solved the problem.
I Added some flag to the C program, in order to give me the directory name i need.

Thanks for help
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