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How to remove space in between the result

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# 1  
Old 08-10-2009
How to remove space in between the result

Hi All,

How do i remove the spaces in between, the outputted result: my output is like below and i dont want spaces between them, how do i do that. I am enclosing the peice of code that does that:-

 if [ $? -eq 0 ]; then
 $ECHO "The Path is:" $OFFERING_FILE_PATH/$z
 $ECHO ""


Words to be searched: CCRCWebServerINSTALLDIR
The Path is: /home/administrator/testfix/install/cc.offering/
<includedShareableEntity id="CCRCWebServerINSTALLDIR">

Words to be searched: ClearCaseAdministrationTools-CINSTALLDIR
The Path is: /home/administrator/testfix/install/cc.offering/
<includedShareableEntity id="ClearCaseAdministrationTools-CINSTALLDIR">

Words to be searched: ClearCaseAdministrationTools-ent-CINSTALLDIR
The Path is: /home/administrator/testfix/install/cc.offering/
<includedShareableEntity id="ClearCaseAdministrationTools-ent-CINSTALLDIR">

# 2  
Old 08-10-2009
It looks like that is from the contents of $Z. How does $Z get defined?
# 3  
Old 08-10-2009
Hi Peterro,

The Z variable is defined as:-
Z=`find $OFFERING_FILE_PATH/$z | xargs grep $i`

Thanks for coming to help again

# 4  
Old 08-10-2009
Ok, what is $i? Is this script really large, or would it be appropriate to post all of it here? What I'm trying to get at is that if you can just gather the data you want, the output won't look so bad. From what I see so far, it looks like your getting too much of something (blank lines) when defining variables.
# 5  
Old 08-10-2009
why do u need the below code from ur code???

 $ECHO ""

# 6  
Old 08-10-2009
There is no problem posting it here:-




Y=`$CAT $FIX_XML_PATH/$FIX_FILE | $GREP id | $AWK '{if($2 ~ /id=/) pri
nt $2}' | $AWK -F"'" '$1 == "id=" {print $2}'`

for i in $Y
 $ECHO "Words to be searched:" $i
 for z in $OFFERING_FILE
   #$ECHO "The Path is:" $OFFERING_FILE_PATH/$z
   #Z=`find $OFFERING_FILE_PATH/$z -exec grep  $i {} \;`
   Z=`find $OFFERING_FILE_PATH/$z | xargs grep $i`

   if [ $? -eq 0 ]; then
   $ECHO "The Path is:" $OFFERING_FILE_PATH/$z
   $ECHO $Z
   $ECHO ""


# 7  
Old 08-10-2009
Yup, I think malcomex999 has the answer. Change the
echo ""

echo "this line intentionally left blank"

and see what you get.

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