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Command filtering ONLY rows NOT beginning with '*'

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# 1  
Old 08-10-2009
Command filtering ONLY rows NOT beginning with '*'

I need a command which filters rows ONLY NOT beginning with '*'

So far I have following NOT sufficient command, because it does not include ALL possible literals except of '*'

grep ^[a-zA-Z0-9' '] INPUT_FILE >>OUTPUT_FILE

Is it possible to write something like



---------- Post updated at 07:54 AM ---------- Previous update was at 07:53 AM ----------

Note: it is bash-shell
# 2  
Old 08-10-2009

# 3  
Old 08-10-2009

# 4  
Old 08-10-2009
Simple rule of shell programming: if you want to match a shell special character like wildcards, escape/quote them:
grep -v '^*' INPUT_FILE >> OUTPUT_FILE

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