Shell Programming and Scripting

Thank´s man.
But can´t you do this somehow with grep and reg. expressions? I have checked man for grep and I see speciall characters like "?" could be helpfull, but I don´t know how to used it.

But thanks tyler_durden, your solution in perl does the trick in this case.

try the negation of grep:
$more file1
field 12345 12345
field 12345
field 12345 123456

$grep -v "[0-9]\{6\}" file1
field 12345 12345
field 12345

I got it!

Code:

 
cat f

field 12345 12345 a
field 12345 a
field 12345 123456 a
field 12345 12345
 
 
grep "^field [0-9]\{1,5\}\( [0-9]\{1,5\}\|\) [a-z]$" f

field 12345 12345 a
field 12345 a

Thanks everyone for help!

Hi,
I've got a file which different lines. There are an sql sentence in each one. It looks like this:

alter table bla bla
insert into bla bla
select bla bla
alter table

I'd like the output to show the matches in the same order as they are in the original file. I think that could be done with the "or" or using regexp.
That is, something like this:

grep "insert into" || "alter table" archivo

So it would show the line either with "insert into" or "alter table", the first matching line

Maybe this is done with regexp, I havent used them much and cant find the way to solve this.

Any help?
Thanks in advance.

Hello.

Per our forum rules, all posts must be in English.

We do provide translation services for posts from English to a number of languages as a benefit to users. However, posts must be in English.

Please repost in English.

Thank you for your cooperation.

The UNIX and Linux Forums.