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grep with regular expression optional value


 
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# 8  
Old 08-07-2009
Thankīs man.
But canīt you do this somehow with grep and reg. expressions? I have checked man for grep and I see speciall characters like "?" could be helpfull, but I donīt know how to used it.

But thanks tyler_durden, your solution in perl does the trick in this case.
# 9  
Old 08-07-2009
try the negation of grep:
$more file1
field 12345 12345
field 12345
field 12345 123456

$grep -v "[0-9]\{6\}" file1
field 12345 12345
field 12345
# 10  
Old 08-07-2009
I got it!
Code:
 
cat f

field 12345 12345 a
field 12345 a
field 12345 123456 a
field 12345 12345
 
 
grep "^field [0-9]\{1,5\}\( [0-9]\{1,5\}\|\) [a-z]$" f

field 12345 12345 a
field 12345 a

Thanks everyone for help!
# 11  
Old 10-05-2009
Two or more strings with grep as arguments

Hi,
I've got a file which different lines. There are an sql sentence in each one. It looks like this:

alter table bla bla
insert into bla bla
select bla bla
alter table

I'd like the output to show the matches in the same order as they are in the original file. I think that could be done with the "or" or using regexp.
That is, something like this:

grep "insert into" || "alter table" archivo

So it would show the line either with "insert into" or "alter table", the first matching line

Maybe this is done with regexp, I havent used them much and cant find the way to solve this.

Any help?
Thanks in advance.

Last edited by Kibou; 10-05-2009 at 10:13 AM..
# 12  
Old 10-05-2009
Hello.

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