Shell script grep help

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# 1  
Old 08-03-2009
Shell script grep help

Hey there, newbie question :

echo "::kmastat" | /usr/bin/mdb -k | grep Total | grep "kmem_*"
Total [kmem_msb] 17326080 432853 0
Total [kmem_va] 426508288 65458 0
Total [kmem_default] 704757760 1572001732 0
Total [kmem_tsb_default] 1277952 3027965 0
Total [segkmem_ppa] 3145728 23 0

I do this on a solaris box, as a part of my shell script to check the total kernel memory usage ...

I want to eliminate the last "Total [segkmem_ppa]" from the list, without hardcoding as grep -v "Total [segkmem_ppa]" as, i dont know what else might include the string kmem at any point.

Any solution ?
# 2  
Old 08-03-2009

grep -v "Total \[segkmem_ppa\]"
# 3  
Old 08-03-2009
echo "::kmastat" | /usr/bin/mdb -k | grep Total | grep "kmem_*"| head -4

# 4  
Old 08-03-2009
Both of the solutions work, but they are hardcoding according to the current output.

Lets say, we dont know how many kmem_*'s are gonna be there in the op, then head -4 wont work..

If segkmem_* is not the only string with kmem included in it, then my result array will include more elements than i need...

# 5  
Old 08-03-2009
do you want to just remove the last line? try
echo "::kmastat" | /usr/bin/mdb -k | grep Total | grep "kmem_*" | sed '$d'

# 6  
Old 08-03-2009
perhaps you want lines which contains '[kmem_' ?

---------- Post updated at 08:20 PM ---------- Previous update was at 08:19 PM ----------

or rather the one which includes 'Total [kmem_' ?
# 7  
Old 08-03-2009
Yes exactly,
I just want lines that include Total [kmem_*]

But if I do a grep kmem, it ends up showing, strings which include kmem, like [segkmem_*....
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