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Sort two columns in a field, one of them being a date

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# 1  
Old 07-28-2009
Sort two columns in a field, one of them being a date


I have a set of columns in a csv file, my first row being an integer and 2nd being a date. I want to first sort it using the first column and then by the second.

for e.g. i have ,


i tried this but wont work because the separator is "," :::

sort -t "," -k1 -k2.7,2.10 -k2.4,2.5M -k2.1,2.2 test.csv > hi.csv

Thanks in advance,
# 2  
Old 07-28-2009
perl may be easy to handle it.

my @arr=<DATA>;
print map {$_->[0]}
	sort {$a->[1] <=> $b->[1] || $a->[2] <=> $b->[2]}
		map {
			my @tmp=split(",",$_);
		} @arr;

# 3  
Old 07-28-2009
If I'm not missing something:

sort -t/ -k1n -k3n -k2n  infile

Last edited by radoulov; 07-28-2009 at 07:18 AM.. Reason: corrected, the previous version was wrong ...
# 4  
Old 07-28-2009
sort  -t/ -k1.1,1.4n -k3n -k2n -k1.6,1.8n test.txt

This should also works fine.. rite..

Please correct me if i am wrong.

Last edited by radoulov; 07-28-2009 at 07:07 AM.. Reason: added code tags
# 5  
Old 07-28-2009
Originally Posted by mac4rfree
sort  -t/ -k1.1,1.4n -k3n -k2n -k1.6,1.8n test.txt

This should also works fine.. rite..

Please correct me if i am wrong.
Hi ,

This will just use the "/" as a separator .. what i am trying to figure out is first sort the 1st column so lets say all 1234 together then within those, the date should be sorted.

# 6  
Old 07-28-2009
 sort -t"," -k1.1,1.4  -k2.7,2.10 -k2.4,2.5 -k2.1,2.2 file


sort -t"," -k1,1n  -k2.7,2.10 -k2.4,2.5 -k2.1,2.2 file

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