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Deleting Doubled Block with sed or awk

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# 1  
Old 07-27-2009
Question Deleting Doubled Block with sed or awk
hi there,

i have a text file like that one:
Quote:
blablabla
blub
bla
Startblabla
texttexttext
texttexttext
texttexttext
Endblabla

Startblabla
texttexttext
texttexttext
texttexttext
Endblabla
blablabla
blub
bla

I like to delete the second block with the Start and End Line!


Quote:
blablabla
blub
bla
Startblabla
texttexttext
texttexttext
texttexttext
Endblabla

blablabla
blub
bla
Does anyone have a idea?

Thanks for your help,

Roland
# 2  
Old 07-27-2009
What have you attempted so far and where do you get stuck?

Regards
# 3  
Old 07-28-2009
At the momentan i have realized it with

Quote:
sed -e '53,84d'
But the lines are very correct.

Than I tried

Quote:
sed -n '/Start*/,/End*/p;/End*/q'
but it just prints that thing I want to delete. Hmmm
And it doesn't test about the dublicity! :-(

Perhaps someone could help me out!

Roland
# 4  
Old 07-28-2009
If Perl is acceptable, you may try something like this:

Code:
perl -0777pe'
  s|(Start.*?End)|$x{$1}++?$/:$1|sge
  ' infile

Last edited by radoulov; 07-28-2009 at 10:00 AM..
# 5  
Old 07-28-2009
You can do something like that :
Code:
awk '(/^Start/ && ++s==2),/^End/ { next } 1 '  inputfile

Inputfile:
Code:
blablabla
blub
bla
Start 1111 blabla
111 texttexttext
111 texttexttext
111 texttexttext
End 1111 blabla

Start 2222 blabla
222 texttexttext
222 texttexttext
222 texttexttext
End 222 blabla
blablabla
blub
bla 
Start 3333 blabla
333 texttexttext
333 texttexttext
333 texttexttext
End 333 blabla
bla

Output:
Code:
blablabla
blub
bla
Start 1111 blabla
111 texttexttext
111 texttexttext
111 texttexttext
End 1111 blabla

blablabla
blub
bla 
Start 3333 blabla
333 texttexttext
333 texttexttext
333 texttexttext
End 333 blabla
bla

Jean-Pierre.
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