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Replacing one Char in a string of variable length


 
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Top Forums Shell Programming and Scripting Replacing one Char in a string of variable length
# 8  
Old 07-28-2009
Solution Achieved

danmero,

Your code worked perfectly. Thank you.

Edidataguy, I was looking for the best approach rather than just looking for someone to provide the code, hence why I did not attach any initial code.

I always try to research approch first then code. I was hoping for a reply like, use Sed, or loop through each bit and replace the one you want, then I would have researched that.

I am new to shell, (used to VB) so I was planning to use grep -c to read each char in turn and just write out to a new string until I got to my bit to change etc... This would have taken 6-7 lines of code but sed, did it perfectly.

I now have ordered a sed book to study.

My final code is below. (echo's will be replaced with a -v for production, and -d for write to log eventually)


while read EachLine
do
SFPSBITS=$(echo "$EachLine" |cut -d":" -f2)
SFRECNO=$(echo "$EachLine" |cut -d":" -f3)
SFPHONESTAT=$(echo "$EachLine" |cut -d":" -f4)
echo "PHONESTAT:$SFPHONESTAT"

echo "Bit to change:$SFPSBITS - Record to change:$SFRECNO"
echo "Current PHONESTAT string is $SFPHONESTAT"

SFNEWPHONESTAT=$(echo "$SFPHONESTAT" | sed "s/./B/$SFPSBITS")

echo "New PHONESTAT string:$SFNEWPHONESTAT"
# `set_field $LISTNO PHONESTAT PSBITS -f $SFRECNO -l $SFRECNO`
done < file4.1.$$
# 9  
Old 07-28-2009
Just making sure that people dont come here with there home work and also that they do really try to resolve.
Code:
OIFS=$IFS
IFS=$':'
position=2; xreplwith="B"
# while read str; do
   str='012341231231:2:102939283:NNN:'
   set $xreplwith $position $(echo "$str")
   echo $3:$4:$5:$(echo $6 | sed "s/./$1/$2"):
# done < file
IFS=$OIFS

Please do the following:
1. May be the hard coded values position=2; xreplwith="B" should be replace with params sent to the script as $1 and $2.
2. Remove the "str=" value.
3. Change the "while read" part as required.

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