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Convert exponential value to decimal

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# 1  
Old 07-22-2009
Convert exponential value to decimal


Here is my script to read a file into array:
awk -F '[ \t$]+' '
# load first file into array indexed by fields 1 and 2
NR == FNR {
file1nr = FNR
for (i=3; i<NF; i++) {
file1[$1,$2,i] = $i

I have this value in file -1191190.11328125, but my script reads it as -1191190.00000
I want to read it as -1191190.11328.

I tried to add a line

$i = sprintf ("%.5d" $i)

But this yields -1191190.00000

Please help.

I tried
I want to read it upto 5 decimal places.

Please help.
# 2  
Old 07-22-2009

It's a floating point number.

try %.5f instead of %.5d
# 3  
Old 07-22-2009
I also tried %.f and it didnot work.

# 4  
Old 07-22-2009
Originally Posted by Sangtha
I also tried %.f and it didnot work.

$i = sprintf ("%.5f", $i)

didn't work?
# 5  
Old 07-23-2009
Yes, thats right. It does display 5 decimal places after, but for some reason, it replaces it with zeros.
# 6  
Old 07-23-2009
echo "-1191190.11328125" | awk '{$0 = sprintf ("%.5f", $0) ;print}' 
yields me 


You might me doing wrong somewhere else.

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