Not able to assign a value to variable

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# 8  
Old 07-22-2009
Nice thought Smilie
but actually the external vendor puts this file into our server,we cannot make any changes to this file.. Smilie
Actually I am thinking if i can create the copy of the source file(config.csv) and then use sed command(replacing the slashes) ...but then will sftp command will work properly?? Smilie
I am not sure if this approach is proper or not Smilie
Anyone have better idea ... Smilie
# 9  
Old 07-22-2009
hehe, just replace the backslashes for the meantime
-bash-3.2$ sed -e 's|\\|/|g' config.csv

# 10  
Old 07-22-2009
Originally Posted by Amey Joshi

$ cat config.csv


echo $line > 45.txt
DataPath=`cat 45.txt | awk -F"," '{print $1}'

DataPath=` .... `
or write it
DataPath=$( .... ) - easier to see and read (and maybe understand = take value of subprocess).
# 11  
Old 07-22-2009
i try that one also, it makes $line value to "homefirdir,filename1,csv"
# 12  
Old 07-22-2009
Double the \ character from the input file and use the print -R command instead of echo :
$ cat config.csv
$ cat amey.ksh
head -5 config.csv | sed 's+\\+&&+g' | while read line
Type1=`echo $line | awk -F"," '{print $3}'`
Type=`echo $Type1 | tr [A-Z] [a-z]`
if [ $Type = 'csv' ]
   DataFileName=`echo $line | awk -F"," '{print $2}'`
   DataPath=`print -R "$line" | awk -F"," '{print $1}'`
   print -R $DataPath
   slash=`echo '\'`
   filelocation=`echo $DataPath$slash$DataFileName`
   echo do sftp -n
$ amey.ksh
do sftp -n
do sftp -n
do sftp -n

Your script can be rewritten in the following form :
typeset -l Type
head -5 config.csv | sed 's+\\+&&+g' |
while IFS=, read DataPath DataFileName Type
if [ "$Type" = 'csv' ]
   print -R  $DataPath
   print do sftp -n

# 13  
Old 07-22-2009
cat config.csv | while read -r line
        [ "$Type" != "csv" ] && continue
        print -R "$Path - $Filename"

# 14  
Old 07-23-2009

Thanks All!!
Both the scripts work really very well... Smilie

Again Many Thanks!!! Smilie Smilie
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