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Shell Programming and Scripting

find and replace query

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# 8  
Old 05-27-2009
Quote:
Originally Posted by devtakh
Code:
sed '/Server=127.0.0.1/{s//Server=0.0.0.0/g}
/ServerPort=0/{s//ServerPort=1/g}
/Enable Server=1/{s//Enable Server=0/g}
' /opt/server.conf > /opt/new_server.conf

-Devaraj Takhellambam
Hi Devaraj Takhellambam,

Your solution works fine... but I am facing new problem now... Actually I didn’t mentioned my complete input file which is
Code:
### Welcome to server ###
### Server address and port ###
 
Server=127.0.0.1 
### Replace Server=0.0.0.0 ###
 
ServerPort=0
### Replace ServerPort=1 ####
### Enable Server ##
 
Enable Server=1
 
### Replace Enable Server=0 ###
 
Enable Agent=1
Enable ip=1
 
### Now I dont need to change above two options ###
### END OF FILE ##

So what i have implemented look like
Code:
FILE="/opt/server.conf"
NEW_FILE="/opt/new_server.conf"
    exec 0<$FILE
    while read line
do
     #echo ${line}
     if [ -n "`echo ${line} | grep 'Server=127.0.0.1'`" ]  #grep command searches for right string
     then
              echo ${line} | sed 's|Server=127.0.0.1|Server=0.0.0.0|g' >>$NEW_FILE
     elif [ -n "`echo ${line} | grep 'ServerPort=0'`" ]
     then
             echo ${line} | sed 's|ServerPort=0|ServerPort=1|g' >>$NEW_FILE
     elif [ -n "`echo ${line} | grep 'Enable Server=1'`" ]
     then
             echo ${line} | sed 's|Enable Server=1|Enable Server=0|g' >>$NEW_FILE
     else
             echo ${line} >>$NEW_FILE
     fi
     done < $FILE

Output file looks like
Code:
Server=0.0.0.0
ServerPort=1
Enable Server=0

So when i execute my code, output file only contains the strings which i have changed, there are certain strings which i want to copy as it .

Sorry i am bothering you lot...

thanks Smilie
# 9  
Old 05-27-2009
follow this code:

find . -type f | xargs sed -i "s/Server=127.0.0.1/Server=0.0.0.0/g"
# 10  
Old 05-27-2009
Quote:
Originally Posted by mnmonu
follow this code:

find . -type f | xargs sed -i "s/Server=127.0.0.1/Server=0.0.0.0/g"
hi mnmonu,

I am still new to shell script, can you explain me as where to and how to use find . -type f | xargs sed -i "s/Server=127.0.0.1/Server=0.0.0.0/g" in my mentioned code..

thanks

-----Post Update-----

hi devtakh

Sorry mate for bothering you with so many question.. There was problem in my script and i found it.. Now output is coming very correctly...

Thanks man.. Really appreciate your response..

Thanks to all who gave their valuable suggestions.
Last edited by lightdensity; 05-27-2009 at 07:57 AM..
# 11  
Old 05-27-2009
hey,

even i was facing similar query.. your posts helped me
# 12  
Old 05-27-2009
Quote:
Originally Posted by devtakh
Code:
sed '/Server=127.0.0.1/{s//Server=0.0.0.0/g}
/ServerPort=0/{s//ServerPort=1/g}
/Enable Server=1/{s//Enable Server=0/g}
' /opt/server.conf > /opt/new_server.conf

-Devaraj Takhellambam
hi,

As soon as i think, i am getting use to shell script .. some or the other errors occurs.
My previous code is working fine execpt for
Code:
 elif [ -n "`echo ${line} | grep 'DAEMON_OPTIONS(`Port=smtp,Addr=127.0.0.1, Name=MTA')dnl'`" ]
 then
       echo ${line} | sed 's|DAEMON_OPTIONS(`Port=smtp,Addr=127.0.0.1, Name=MTA')dnl|DAEMON_OPTIONS(`Port=smtp,Addr=0.0.0.0, Name=MTA')dnl|g' >>$FILE1

this is throwing error
Code:
./sendmail.sh: line 19: unexpected EOF while looking for matching ``'
./sendmail.sh: line 33: syntax error: unexpected end of file

Pl me help on this..
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