Login or Register to Ask a Question and Join Our Community


Shell Programming and Scripting

Help with awk

Login to Discuss or Reply to this Discussion in Our Community

 
Thread Tools Search this Thread
Top Forums Shell Programming and Scripting Help with awk
# 1  
Old 05-26-2009
Help with awk
Hi Guys,,

I am assigning a query result to a variable.

variable=`db2 -x "select col1 from table1 | awk '{print $1}'`

The problem is if i execute the above command without awk. I am getting an value. But if i execute with awk command, i am getting an error, saying
A database connection does not exists.

I want the awk command to be used.

Please help me.

Thanks for your help in advance,
Magesh
# 2  
Old 05-26-2009
Code:
variable=`db2 -x "select col1 from table1`

is it correct ?.. i can see only one double quote ".

how ever u can try somethng like this

Code:
variable1=`db2 -x "select col1 from table1"`
variable=`echo "$variable1" | awk '{print $1}' `

# 3  
Old 05-26-2009
Panyam, i made a mistake while typing it in the forum. its having double quotes..
And i tried your suggestion already. It is still showing the same output with the error.
A Database connection does not exist
# 4  
Old 05-26-2009
Code:
variable=`db2 -x "select col1 from table1 | awk '{print $1}'`

The problem is if i execute the above command without awk. I am getting an value.


I am sure that,

Code:
variable=`db2 -x "select col1 from table1"`

( with out awk )

also wont return anything and ther is some issue with the data base connectvity. Because the next awk statemnt is nothng to do much other than priting.
# 5  
Old 05-26-2009
correct panyam, i too thought so. When i execute it in the command line. i am getting the value. But when i put it in the script, the value is not getting assigned to the variable.
The code in the scripts is
PREVIOUS_QTR=`db2 -x "SELECT statement"`
PREVIOUS_QTRAPPLBTY= `echo "$PREVIOUS_QTR" | awk '{print $1}'`
echo $PREVIOUS_QTRAPPLBTY

in the verbose mode, i got this

PREVIOUS_QTR= 200901

PREVIOUS_QTRAPPLBTY= `echo "$PREVIOUS_QTR" | awk '{print $1}'`
+ awk {print $1}
+ echo 200901
+ 200901
+ PREVIOUS_QTRAPPLBTY=
genTmGapQTR.ksh[22]: 200901: not found.
echo $PREVIOUS_QTRAPPLBTY
+ echo


Please help me.. in this
# 6  
Old 05-26-2009
Code:
PREVIOUS_QTRAPPLBTY= `echo "$PREVIOUS_QTR" | awk '{print $1}'`

remove the space after the "=". I can see a single space after =.
# 7  
Old 05-26-2009
Thanks dude.. it worked man..
Login or Register to Ask a Question

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

awk output yields error: awk:can't open job_name (Autosys)

Good evening, Im newbie at unix specially with awk From an scheduler program called Autosys i want to extract some data reading an inputfile that comprises jobs names, then formating the output to columns for example 1. This is the inputfile: $ more MapaRep.txt ds_extra_nikira_usuarios... (18 Replies)
Discussion started by: alexcol
18 Replies

2. Shell Programming and Scripting

Pass awk field to a command line executed within awk

Hi, I am trying to pass awk field to a command line executed within awk (need to convert a timestamp into formatted date). All my attempts failed this far. Here's an example. It works fine with timestamp hard-codded into the command echo "1381653229 something" |awk 'BEGIN{cmd="date -d... (4 Replies)
Discussion started by: tuxer
4 Replies

3. Shell Programming and Scripting

Passing awk variable argument to a script which is being called inside awk

consider the script below sh /opt/hqe/hqapi1-client-5.0.0/bin/hqapi.sh alert list --host=localhost --port=7443 --user=hqadmin --password=hqadmin --secure=true >/tmp/alerts.xml awk -F'' '{for(i=1;i<=NF;i++){ if($i=="Alert id") { if(id!="") if(dt!=""){ cmd="sh someScript.sh... (2 Replies)
Discussion started by: vivek d r
2 Replies

4. Shell Programming and Scripting

HELP with AWK one-liner. Need to employ an If condition inside AWK to check for array variable ?

Hello experts, I'm stuck with this script for three days now. Here's what i need. I need to split a large delimited (,) file into 2 files based on the value present in the last field. Samp: Something.csv bca,adc,asdf,123,12C bca,adc,asdf,123,13C def,adc,asdf,123,12A I need this split... (6 Replies)
Discussion started by: shell_boy23
6 Replies

5. Shell Programming and Scripting

awk command to compare a file with set of files in a directory using 'awk'

Hi, I have a situation to compare one file, say file1.txt with a set of files in directory.The directory contains more than 100 files. To be more precise, the requirement is to compare the first field of file1.txt with the first field in all the files in the directory.The files in the... (10 Replies)
Discussion started by: anandek
10 Replies

6. Shell Programming and Scripting

Comparison and editing of files using awk.(And also a possible bug in awk for loop?)

I have two files which I would like to compare and then manipulate in a way. File1: pictures.txt 1.1 1.3 dance.txt 1.2 1.4 treehouse.txt 1.3 1.5 File2: pictures.txt 1.5 ref2313 1.4 ref2345 1.3 ref5432 1.2 ref4244 dance.txt 1.6 ref2342 1.5 ref2352 1.4 ref0695 1.3 ref5738 1.2... (1 Reply)
Discussion started by: linuxkid
1 Replies

7. Shell Programming and Scripting

Problem with awk awk: program limit exceeded: sprintf buffer size=1020

Hi I have many problems with a script. I have a script that formats a text file but always prints the same error when i try to execute it The code is that: { if (NF==17){ print $0 }else{ fields=NF; all=$0; while... (2 Replies)
Discussion started by: fate
2 Replies

8. Shell Programming and Scripting

awk: assign variable with -v didn't work in awk filter

I want to filter 2nd column = 2 using awk $ cat t 1 2 2 4 $ VAR=2 #variable worked in print $ cat t | awk -v ID=$VAR ' { print ID}' 2 2 # but variable didn't work in awk filter $ cat t | awk -v ID=$VAR '$2~/ID/ { print $0}' (2 Replies)
Discussion started by: honglus
2 Replies

9. Shell Programming and Scripting

scripting/awk help : awk sum output is not comming in regular format. Pls advise.

Hi Experts, I am adding a column of numbers with awk , however not getting correct output: # awk '{sum+=$1} END {print sum}' datafile 2.15291e+06 How can I getthe output like : 2152910 Thank you.. # awk '{sum+=$1} END {print sum}' datafile 2.15079e+06 (3 Replies)
Discussion started by: rveri
3 Replies

10. Shell Programming and Scripting

Awk problem: How to express the single quote(') by using awk print function

Actually I got a list of file end with *.txt I want to use the same command apply to all the *.txt Thus I try to find out the fastest way to write those same command in a script and then want to let them run automatics. For example: I got the file below: file1.txt file2.txt file3.txt... (4 Replies)
Discussion started by: patrick87
4 Replies
Login or Register to Ask a Question