Shell Programming and Scripting

Hello,

I want to know how i can sum two numbers in a grep command with the parameter -n.
this code return line number and the line who have the "pattern" :
[
cat fileName | grep -i "pattern" -n $(cat fileName | grep -i "pattern" | sed -n 's/^\([0-9]*\)[:].*/\1/p')
]

but now i want to suw [$(cat fileName | grep -i "pattern" | sed -n 's/^\([0-9]*\)[:].*/\1/p')] with 1 to have the next line:
[$(cat fileName | grep -i "pattern" | sed -n 's/^\([0-9]*\)[:].*/\1/p')] + 1 : it can't work.


Thanks you

Can you explain what exactly you are trying to accomplish here? Also, if you paste the input file sample and the expected o/p, it will be easier for us to help.

grep with an option of n prints the line number with the o/p line. and you want to use this line number to do something?

If you are trying to o/p the next line where a pattern matches, you can try something like this

Code:

 awk '$0 ~ /pattern/{getline;print;exit}' filename

cheers,
Devaraj Takhellambam

My idea is to extract the line number and add this line with +1.
An example with this line who is in the file "file.dat":
"3 :reserved xxxxxxxxxxxxxxxxxxxxxxxx"
"4 :xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx"
"5 :reserved xxxxxxxxxxxxxxxxxxxxxxxxxx"
"6 :xjlkllssssssssssssssssssssssssssssssshh"

To extract the line number, i do that :
[cat file.dat | grep -i "reserved" -n $(cat file.dat | grep -i "reserved" | sed -n 's/^\([0-9]*\)[:].*/\1/p')] and i have the line number only (3 and 5).

The next step that i want , it's to make the same thing with the same command but add "+1" to the extracted number of the line and to print lines 4 and 6.
[cat file.dat | grep -i "reserved" -n $(cat file.dat | grep -i "reserved" | sed -n 's/^\([0-9]*\)[:].*/\1/p') + 1 ] but it don't work.

Thanks you.

It's not clear what you're trying to achieve, better is to provide an example of the input file and the desired output.

Regards

Here's one way:

Code:

$
$
$ cat file.dat
3 :reserved xxxxxxxxxxxxxxxxxxxxxxxx
4 :xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
5 :reserved xxxxxxxxxxxxxxxxxxxxxxxxxx
6 :xjlkllssssssssssssssssssssssssssssssshh
$
$ awk -F" :" '/reserved/ {getline; print $1}' file.dat
4
6
$

and here's another:

Code:

$
$ perl -ne '{next if /reserved/; split/ :/; print $_[0],"\n"}' file.dat
4
6
$

HTH,
tyler_durden