Shell Programming and Scripting

I agree to this. We should probably have a counter appended to the new filenames.

Code:

mv "$file" "COM_$i_$(date + "%Y%m%d").txt"

and increment i for each file. just a thought but depends on the exact requirement.

Hi all,

Let me explain ya..

In folder A, there are several file with different name.
Example :

PTWO121.txt
PTWO122.txt
PONE145.txt
PTWO151.txt
PONE181.txt
PTWO191.txt

I only want to grep the file that the name start with PTWO and rename it to COM and current date.

Desired output :

COM20090412.txt
COM20090412.txt
PONE145.txt
COM20090412.txt
PONE181.txt
COM20090412.txt

Thanks for your help~

It's not possible to have 4 files with the same name in a directory.

Two different files can't have the same name. It will overwrite the exiting one when you try to move another one with the same name. That is why I am suggesting you have filenames like below. If that works out for you, you can use my old code with the i.
COM_1_20090412.txt
COM_2_20090412.txt

Hi all,

Thanks Franklin52 for the reminder.

This is my desired output :

COM20090412_1.txt
COM20090412_2.txt
PONE145.txt
COM20090412_3.txt
PONE181.txt
COM20090412_4.txt

To devtakh : The script that you give hit an error.

I still can't solve it..

Thanks for your help~

What is the script you are using and what is the error it is giving.

Here is the code for your issue.

=========code================

count=`ls PTWO* | wc -l`
old=PTWO
day=`date +%Y%m%d`
new=COM$day

while [ "$count" -gt 0 ]
do
count=`ls PTWO* | wc -l`
file=`ls PTWO* | tail -1`
newfile=`echo "$file" | sed "s|"$old"|"$new"|g"`
mv $file $newfile > /dev/null

done

echo " RENAME DONE"