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Shell Programming and Scripting

making sure my string is [a-z] only

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# 15  
Old 04-24-2009
Sorry, I cannot reproduce (there is a syntax error in the example you posted, a missing space after the first == operator, is it a typo?).

Could you copy/paste the exact command(s) you are running and all the output you get?
# 16  
Old 04-24-2009
inicidentally, ive tried within my script doing this

Code:
#!/bin/bash
LANG=C

echo "Please enter VAR: "
read VAR

case $VAR in
  "" | *[!a-z]* ) echo invalid ;;
              * ) echo ok ;;
esac

Still returns OK when a capital letter is input Smilie
# 17  
Old 04-24-2009
Try with LC_ALL instead of LANG. Is the case-less version working?
# 18  
Old 04-24-2009
apologies for the syntax error, I corrected the space and it all works fine, script below

Code:
if [[ $VAR == *[^[:lower:]]* || $VAR == "" ]] ; then
echo invalid
else
echo ok
fi

just to let you know though that I cant seem to get the "LANG=C" within the script way to work.

Thank you very very much for your help Radoulov
# 19  
Old 04-24-2009
Perhaps a solution ???

echo $var | grep -E [a-z]
# 20  
Old 04-24-2009
Quote:
Originally Posted by hcclnoodles
[...]just to let you know though that I cant seem to get the "LANG=C" within the script way to work.
Even after setting LC_ALL=C (see my previous post)?
# 21  
Old 04-24-2009
LC_ALL works ! .

thank you again

Code:
#!/bin/bash
LC_ALL=C
read VAR


case $VAR in
  "" | *[!a-z]* ) echo invalid ;;
              * ) echo ok ;;
esac

~
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