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Problen in a bash script

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Top Forums Shell Programming and Scripting Problen in a bash script
# 1  
Old 03-05-2009
Problen in a bash script
Hi

New post, and new member

I have a problem with a bash script
And I probably look't at for so long that I DON'T
See a obvious syntax error

The reason for the script is to selectively change permission, UID, GID within
A selected /dir
Anny help or insight would be appreciated
Dan

So the offending part of the script is

# main execution
for i in "${DIR}"; do

if [ -f "$i" = ${DIR} ]; then
echo "${DIR}":" skipping modifing ${DIR} no sutch dir exist" && continue
else
[ -f "${DIR}" ] && { chown "${USR}":"${GID}" ; }{ chmod "${MOD}"; ] && echo ls -als ${DIR};
fi

done

The output I get
+ DIR=
+ MOD=
+ USR=
+ GID=
+ NAM=
+ PA=
+ getopts vhlp:d:u:g: options
+ case "$options" in
+ DIR=/home/user
+ getopts vhlp:d:u:g: options
+ case "$options" in
+ MOD=755
+ getopts vhlp:d:u:g: options
+ case "$options" in
+ USR=user-name
+ getopts vhlp:d:u:g: options
+ case "$options" in
+ GID=staff
+ getopts vhlp:d:u:g: options
+ [[ -n /home/user ]]
./chgfile.sh: line 62: syntax error near unexpected token `fi'
./chgfile.sh: line 62: ` fi'
# 2  
Old 03-05-2009
Quote:
Originally Posted by Ex-Capsa
Hi

New post, and new member

I have a problem with a bash script
And I probably look't at for so long that I DON'T
See a obvious syntax error

The reason for the script is to selectively change permission, UID, GID within
A selected /dir
Anny help or insight would be appreciated
Dan

So the offending part of the script is

Code:
# main execution
for i in "${DIR}"; do


Why do you have a for loop? SInce you only give it one item, it is unnecessary.
Quote:
Code:
 
    if [ -f "$i" = ${DIR} ]; then


Here you should get an error message, "[; too many arguments"

Do you mean:

Code:
if [ -f "$i" ]

But why would you test a directory with the file test?

Presumably what you want is:
Code:
if [ -d "$i" ]

Quote:
Code:
        echo "${DIR}":" skipping modifing  ${DIR} no sutch dir exist" && continue
    else
        [ -f "${DIR}" ] && { chown "${USR}":"${GID}" ; }{ chmod  "${MOD}"; ] && echo ls -als ${DIR};
    fi

# 3  
Old 03-05-2009
The answer to both of your remarks
Are simple

1# The script is a adaptation to a earlier script that I wrote for file manipulation
2# I was beginning to be tired and could not see the obvious

And you showed me the way it works now

Thank you very much ;-)
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