Shell Programming and Scripting

Please help.....

if i have a file list below :

1233743158.log
1233743410.log
1233744186.log
1233744462.log

"1233743158" is a unix time format

it's require to a script "convertime.sh" to convert unix time format to readable time format like 20090204183010 -- YYYYMMDDHHMMSS

script for convert from unix time sentence
# ./convertime.sh -d 1233743410 +%Y%m%d%H%M%S
20090204183010


i want to write a scrpit (inside use the script "convertime.sh") to generate the command like below:

cp 1233743158.log 20090204182558.log
cp 1233743410.log 20090204183010.log
cp 1233744186.log 20090204184306.log
cp 1233744462.log 20090204184742.log

Hi,

Sorry Not sure what you are trying to say...

if you want to change file name with respective timestamp then..

we can use below command inside script.....

cp 1233743158.log `date +%Y%m%d%H%M%S`.log

what else you want to do here..

Thanks
Sha

if using your command only can copy the file to current time not file's real time


1233743158.log is a file name

"1233743158" is a unix time format

it's require to a script "convertime.sh" to convert unix time format to real time format like 20090204183010 -- YYYYMMDDHHMMSS

if run the script convertime.sh like below

# ./convertime.sh -d 1233743158 +%Y%m%d%H%M%S
result printout

20090204182558 <--readable time for the file 1233743158

file.list's content is below ??

1233743158.log
1233743410.log
1233744186.log
1233744462.log

how to apply this with convertime.sh ??

if you have *.log files in specific location:
then try the below one..


n=1
for f in `ls *.log`
do
cp $f `date +%Y%m%d%H%M%S`_$n.log
n=$(( n + 1 ))
done

Thanks
Sha

You don't need the convertime.sh this basic script will do what you want.

Code:

#!/bin/sh
while read name
do
   echo cp "$name" `date -d "${name%.*}" "+%Y%m%d%H%M%S"`.log
done < file.list

Replace the file.list by your file name, check the output and when you are satisfied remove the echo.

and please read some "Scripting for beginners"