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Hi Sea,

The behaviour of printf and echo are different.

$ echo This is piped
This is piped
and
$ echo "This is piped"
This is piped

produce the same output*, but this is not the case...

grep -E '^filename-([0-9]+\.){3}tar\.gz' file

The caret sign (^)means that the expression only matches text at the beginning of the line.
There already had be a space at the end.
These two measures make that a partial match will not work.

Hi, try:
grep "^${disk1} " -o --max-count=1

Try:
awk -F, '$3=="bcd"{$0=$0 FS substr($NF,4,1)}1' file

Do you mean the Network Information Service schema for LDAP?
RFC 2307 - An Approach for Using LDAP as a Network Information Service (https://tools.ietf.org/html/rfc2307)
and
Or perhaps the...

You're welcome..

Awk is somewhat unique in the sense that it allows you to specify a different record separator, other than the typical newline, which is absent in your case.

By specifying a...

Unix utilities typically need a linefeed at the end of the line. You could try awk:

awk '/test12-42213.devserver.com/,/EndTime/; END{printf "\n"}' RS=, ORS=, file
or
awk -v...

Why single line? Another croc to try:
awk 'NR>2{e="N"; exit 1} END{printf "##### THE LOTC cluster state IS %sOK ##########\n",e}' file

awk '/Start/{p=$0; next} p{p=p ORS $0} /End/{if(p~/12345/)print p; p=x}' file

Or, using vertical real estate:
awk '
/Start/ {
buffer=$0
next
}
buffer {
buffer=buffer ORS...

You need to use double quotes, rather than single ones in this case. Shell variables inside single quotes do not get expanded.

Hi, it does not work that way. Instead try:
oflnb=${oflna%.*}

Not sure if this applies here. One time I came across a excessive load pattern with no increase of cpu and io, was when there were a lot of processes in uninterruptible sleep state (D), which...

Ah I see OK

By the way I suggested "%6s" rather than "%6d" to avoid the octal thing...

A quick note to add:
numbers=$(printf "%6s" $number)
numbers=${numbers// /0}
could also be combined as:
numbers=$(printf "%06s" "$number")

Thank Neo, for this great honour and your kind words!

I agree that there are many who deserve this title and I feel honoured to be among them..

I am glad to be part of this wonderful community...

Try this adaptation of RudiC's suggestion:

awk '
/@inlineifset/ {
if(/@btpar/) {
$1 = $1
gsub(/@inlineifset{mrg, @btpar{@|,,,,}}/, "")
}
print
}
' RS=...

Using RudiC's suggestion of -M , using GNU sort
sort -k4n -k1,1M -k2,3n file
Would complete the sort.

Good to hear the suggestion seems to work out for you :)
Let me explain what it means:
while ( ytd_date !~ /^[01][0-9][0-3][0-9][901][0-9]$/ ) {
This is a so-called "regular expression" , which...

Hi,

Try changing:
while ( ytd_date !~ /^[01][0-9][0-3][0-9][901][0-9]$/ ) {
into
while ( ytd_date !~ /^[01][0-9][0-3][0-9][0-9][0-9]$/ ) {
and try and test if that might work out for you...

To get just the filename you can use ${f##*/} instead of $f (within double quotes)

Hi, a pipe appears to be missing:
egrep -v '^listener' |\

Hi some quick thought on the last code snippet:
In awk the middle section is processed per line, so you should leave out:
for(i=1;i<=NR;i++)
The results should be stored in arrays so they can be...

Can you specify what does not work? The message presented is just a warning caused by the unnecessary backslash before the semicolon, but it should not change the outcome.

Here are some more alternatives to try:

Use a here string
read var1 var2 <<< "$(openstack hypervisor stats show | awk -F'|' 'NR==14{print $2,$3}')"
Use a here document
read var1 var2 << EOB
...