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$ sort -t"," -k1,1 -u file
ENSG00000003137,ENST00000001146
ENSG00000003402,ENST00000309955

ls | awk -F"status_|[.]log" ' { print $2 } '

Can you post expected output?

Can you post what you tried?

$ cat check.sh
fileprops="-rwxrwxrwx user1 2019-08-31 17:36 /fin/app/01/scripts/filename6.src 4294967295"
echo "FILE PROPERTY: $fileprops"
echo "PARAMETER3: $1"

if [[ "$1" ==...

$ cat check.sh
str=`echo $1 | sed -e 's#[\][\]n# #g'`
echo $str>check.now
$ bash -x ./check.sh '/fin/app/01/scripts\\n/fin/app/01/sql'
++ echo '/fin/app/01/scripts\\n/fin/app/01/sql'
++ sed -e...

$ sed -e 's/[^\t]*id/& \ /g' -e 's/[^\t]*alias_./& \ /g' file
Chr1 lnci exon 83801516 83803251 . - . gene_id "LINC01725"; transcript_id "LINC01725:44"; ...

Can you post what you tried?

$ echo '/fin/app/scripts\\n/fin/app/01/sql' | sed -e 's#\\\\n# #g';
/fin/app/scripts /fin/app/01/sql
$ echo '/fin/app/scripts\\n/fin/app/01/sql' > file
$ sed -e 's#\\\\n# #g' file...

$ echo $str | sed -e 's#\\n# #g';
/fin/app/scripts /fin/app/01/sql

If you don't have ">" in your input before vehicle then try
awk -v Tyre='Four' ' $0 ~ /Vehicle:/ { veh=$2 } $0 ~ "Tyre : "Tyre { print veh } ' file

Or

$ awk -v Tyre='Four' ' $0 ~ /Vehicle:/ {...

$ awk -v Tyre='Four' ' $0 ~ /Vehicle:/ { veh=$0 } $0 ~ "Tyre : "Tyre { print veh } ' file
> Vehicle: BMW Class
Vehicle: Toyota Class

Can you post what you have tried?

Can you post expected output?

$ awk ' FNR == NR { ky=$4; sub("_.*","",ky); arr[ky]=$0; next } {print arr[$1]} ' content.xls id.txt
NC_020815.1 1891831 1894692 virb4_A0A0H2X8Z4_ 1 954 1945
NC_020815.1 ...

$ awk -v RS="\nName:" -v OFS="," -v FS="\n" -v ORS="\nName:" ' { print $1 OFS $2 ($3 ? OFS $3 : "") } ' file
Name: serve1,has disk :Yes,dev (8):
Name: serve2,has disk :No,dev (8):
Name: serve3,has...

$ awk '{ currKey = $2 }
> currKey != prevKey { prt(); min=$3; cnt=0 }
> { prevRec=$0; prevKey=currKey; max=$3; cnt++ }
> END { prt() }
>
> function prt( f) {
> if ( cnt ) {
> ...

$ cat file
=(root)NOPASSWD:/usr/bin/vim
=(ALL)NOPASSWD:/usr/bin/vim
=NOPASSWD:/usr/bin/vim
=(user)NOPASSWD:/usr/bin/vim
$ egrep '=(\(root\)|\(ALL\))?NOPASSWD' file
=(root)NOPASSWD:/usr/bin/vim...

If you want to print block which contains pattern devId="number"

awk -v RS="</alarms>" -v ORS="</alarms>" ' devId="number" ' logfile

Can you post expected output?

Yes

Yes but use double quotes for variable substitution
var=1
sed "${var}..." file

You can add line number like this to run substitute only on first line
sed -i "1{s/{+//;s/+}//;}" error.txt

$ echo '[string 1 ] apple [ string 2]' | perl -pi -e ' s/[[][^]]*]//g; '
apple

$ awk -F'\\]|\\[|-|:' -v RS='\n>' ' NR == FNR { gsub(" ",""); arr[$3]=1;next} arr[$2]{print ">" $0} ' f1 f2
>Contig_152:50833-51615
CGGAGTAGCTTCGATCAGCGTGACCGGTACCGAGCGACCGTCTTCAGTGAAGACGCGGCT...