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It is not solved by above code. if you have several lines, you calculate wrong.

try this:
grep -o "\." infile|wc -l
awk '{sum+=gsub(/\./,"")}END{print sum}' infile

ls ba[aeiou]*

so why not go through the manual by yourself first?

http://linux.die.net/man/8/fence_ilo

what to check? content, file size, or others?

For example, check if the file is same or not on 111 and 222.

have ssh set between 111 and 222:

diff <(ssh user@host222 md5sum /path/file)...

how about this, it is not exact for your request, but get mostly.

perl -l40pe 's/^-+/\n/' svn.log|awk -F \| '{$3=""}1'

r7351 user01 2 lines Changed paths: D /trunk/demo/proj1/.project ...

https://www.unix.com/unix-advanced-expert-users/145472-use-cron-run-job-every-other-week.html

# "first" friday -- and note # generally does work in crontab files as a comment
0 8 ** 6 [ $(( $((...

awk 'NR>2{$0="NEW" RS $0}1' saved_doc

#!/usr/bin/bash
FILE=/home/home1/name.csv
if [ ! -f $FILE ] ; then
echo " file $FILE is not exist"
exit
fi

awk -F , 'int($4)!="0"||int($5)!="0" {printf "ref_num:%s\nAccount...

No need shell script.

There are several add-on in Firefox, seach by keyword "record", you will get several.

Get non-zero number

while :
do
echo "Enter another number."
read num2
if [[ $num2 -eq 0 ]]; then
echo "divide by zero, try again"
else
break
fi
done

so what did you try? Here are hints.

-f FILENAME can be used to identify if the file is exist or not.

awk can be used to get the report.

with this sample:

Table 1:-
DateID
KeyColumn
Field 1
Field 2

Table 2:-
KeyColumn
Field 2
Field 3


from DateID, I can find out the keyColumn, then is keyColumn unique that I can use...

Did you try my code? It has fixed your issue.

Need GNU date command:

#! /bin/bash
d=$(date -d "-30 days" +%Y%m%d%H%M%S)

awk -v d=$d '{split($3,a,"-");split($4,b,":")
s=sprintf("%04d%02d%02d%02d%02d%02d",a[1],a[2],a[3],b[1],b[2],b[3])...

I get the answer same as in your first post.
awk '$5!="0"||$7!="0"' number

DirB port 71 er_enc_out 56 er_bad_os 0
DirB port 75 er_enc_out 0 ...

Ok, for example, you have a gz log file named access.2013-08-13.log.gz

You save below line in a script file name batka.sh

cat batka.sh

gzcat $1|awk '/Received XML TextMessage/{print RS s RS...

awk '$5!="0"||$7!="0"' number

I don't see your script. So you have to show us first.

If you is talking about gzip log, you may try this:

gzcat LOGFILE|awk '/Received XML TextMessage/{print RS s RS $0}{s=$0}' RS="2013-"

This command is not 100% suitable, has some limits.

Limit 1: All logs in 2013
Limit 2: No key "2013-" in any other place, only found at first in each line.

awk '/Received XML...

:):):):):)

awk 'NR==FNR{a[$1 FS $2];next} !($1 FS $2 in a)' file2 file1

sc2/10 10 . G C 50 F=5;U=4
sc2/24 24 . T G 31 F=5;U=4
sc2/11 30 . A T 60 F=5;U=4

this command is correct, what mail client did you use?

Can you try to send to a gmail?

so what's the reason to set another array b?
awk '{a[$0]++} END{for(i in a){if (a[i]==1) {print i}}}' infile

df -k /oradata

or

mount |grep oradata

:):):):):):):)