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# 8  
Old 06-14-2012
Quote:
Originally Posted by vlm
Actually I changed the
Code:
a[i]

to
Code:
&a[i]

and works fine.
It's still wrong. The compiler can't understand your intent here, it can only tell you when something's syntactically wrong.

If you want to pass the array element and not the array itself, that's a void *, not a void **.
# 9  
Old 06-14-2012
Quote:
Originally Posted by Corona688
It's still wrong. The compiler can't understand your intent here, it can only tell you when something's syntactically wrong.

If you want to pass the array element and not the array itself, that's a void *, not a void **.
That's strange because not only compiles fine but works as well...
So if I want to pass the whole array I have to do it the way I said before?
# 10  
Old 06-14-2012
Quote:
Originally Posted by Corona688
It's still wrong. The compiler can't understand your intent here, it can only tell you when something's syntactically wrong.

If you want to pass the array element and not the array itself, that's a void *, not a void **.
It is actually correct since &a[i] is void** not void*...unless i am not gettng your drift...
# 11  
Old 06-14-2012
Quote:
Originally Posted by vlm
That's strange because not only compiles fine but works as well...
It might help if you posted the contents of // do things

I've seen situations in C where two opposite mistakes made the code work fine. I'm still not convinced the code works quite the way you think it does.
# 12  
Old 06-14-2012
Quote:
Originally Posted by shamrock
It is actually correct since &a[i] is void** not void*...unless i am not gettng your drift...
It's syntactically correct, but that doesn't mean it's logically correct. That he's taking the array index makes me suspect he wants the content of the array, but the ampersand makes it a pointer pointer again...
# 13  
Old 06-14-2012
Quote:
Originally Posted by vlm
That's strange because not only compiles fine but works as well...
It works because you got it right...
Quote:
Originally Posted by vlm
So if I want to pass the whole array I have to do it the way I said before?
To pass whole array supply its name as argument to fun like "fun(a)"...even fun(&a[0]) works since array name "a" is a pointer to a[0]...

---------- Post updated at 03:15 PM ---------- Previous update was at 03:10 PM ----------

Quote:
Originally Posted by Corona688
It's syntactically correct, but that doesn't mean it's logically correct. That he's taking the array index makes me suspect he wants the content of the array, but the ampersand makes it a pointer pointer again...
Ah my bad Smilie since you are hinting at the semantics...
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