because below code of line is not inserting value of $DATEGEN to date_gen.
To get value of DATEGEN I did that and I got the value as shown in above thread.
because below code of line is not inserting value of $DATEGEN to date_gen.
...
Can you prove your claim with a clean, short, complete and easy-to-understand testcase ?
Remove all the extra fluff, reduce your script to the bare minimum, concentrate on just the one thing you are trying to do, and show us how it does not work.
Thanks a lot for your time and sugessions.
Now I got the solution of my problem, Here is shell script part of code change
Using above syntax I am able to insert records into my table as,
Good evening
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