Programming

#include <iostream>
#include <stdexcept>
using namespace std;
template <class T>
class Array
{
   public:
      T& operator[] (unsigned i) throw(out_of_range)
      { return data_[i]; }
   protected:
      T data_[100];
};
int main(void)
{
   Array<int> a;
   a[0] = 42;
   a[1] = 10;
   cout<<a[0]<<endl;
#ifdef TEMP
   //How to make this work
   for ( Array<int>::iterator it=a.begin() ; it != a.end(); it++ )
      cout << " " << *it;
#endif
}

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

class array
{
public:
  array(int Size)
  {
    values=(int *)malloc(sizeof(int) * Size);
    len=Size;
    memset(values, 0, Size*sizeof(int));
  }

  int &operator[] (int i) { return(values[i]); }
  int size() { return(len);     }

  class iterator
  {
  public:
        iterator(array *A=NULL, int off=0)      {       a=A;    p=off;  }

        bool operator ==(const iterator &oe)
        {       return( (oe.a == a) && (oe.p == p) );   }
        bool operator !=(const iterator &oe)
        {       return(! ((*this) == oe)        );      }

        iterator &operator++(void)
        {
                if(p < a->size())       p++;
                return(*this);
        }

        int &operator *(void)   {       return((*a)[p]);        }

  private:
    array *a;   int p;
  };

  iterator begin()
  {     return(iterator(this)); }

  iterator end()
  {     return(iterator(this, len));    }

private:
  int *values;
  int len;
};

int main(void)
{
  int n;
  array arr(10);

  for(n=0; n<10; n++) arr[n]=n;

  array::iterator i=arr.begin();
  while(i != arr.end())
  {
    printf("got %d\n", *i);
    ++i;
  }
}