STL Iterator and user-defined class

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# 1  
Old 08-11-2009
Question STL Iterator and user-defined class

Is is possible to make STL-Iterator to work with user defined class ,like the one below?
#include <iostream>
#include <stdexcept>
using namespace std;
template <class T>
class Array
      T& operator[] (unsigned i) throw(out_of_range)
      { return data_[i]; }
      T data_[100];
int main(void)
   Array<int> a;
   a[0] = 42;
   a[1] = 10;
#ifdef TEMP
   //How to make this work
   for ( Array<int>::iterator it=a.begin() ; it != a.end(); it++ )
      cout << " " << *it;

If yes,please explain with example
# 2  
Old 08-11-2009
You'd be writing your own iterator, not using STL's iterator. It involves nested classes.

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

class array
  array(int Size)
    values=(int *)malloc(sizeof(int) * Size);
    memset(values, 0, Size*sizeof(int));

  int &operator[] (int i) { return(values[i]); }
  int size() { return(len);     }

  class iterator
        iterator(array *A=NULL, int off=0)      {       a=A;    p=off;  }

        bool operator ==(const iterator &oe)
        {       return( (oe.a == a) && (oe.p == p) );   }
        bool operator !=(const iterator &oe)
        {       return(! ((*this) == oe)        );      }

        iterator &operator++(void)
                if(p < a->size())       p++;

        int &operator *(void)   {       return((*a)[p]);        }

    array *a;   int p;

  iterator begin()
  {     return(iterator(this)); }

  iterator end()
  {     return(iterator(this, len));    }

  int *values;
  int len;

int main(void)
  int n;
  array arr(10);

  for(n=0; n<10; n++) arr[n]=n;

  array::iterator i=arr.begin();
  while(i != arr.end())
    printf("got %d\n", *i);

Last edited by Corona688; 08-11-2009 at 12:38 PM.. Reason: expanded the example
# 3  
Old 08-12-2009
Thanks for your time in explaining me with an example.
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