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if is a conditional statement not looping !

while, for are loop statements...

Expecting this ..??

if [ condition1 ]; then
export 1
elif [ conidtion2 ]; then
export 2
elif [ condition3 ]; then
export 3
else
export 4
fi

mirni's suggestion is fine if there won't be a case where

ls siv*
siv4211 siv4215 siv4217
dir0=siv4216
...

Better yet, you could do:
last_version=`ls -d siv[0-9]* | sort -n | tail -n 1`

That is,

dir0=siv4210
dirNoVer=${dir0%%[0-9]*} #'siv'
dirLastVer=$(ls -d ${path}/${dirNoVer}[0-9]* | sort -n |...

Try this construct

while [ ! -e $filename ] && [ $(( ${#filename} - 1 )) -ne 0 ]
do
filename=${filename:0:$(( ${#filename} - 1 ))}$(( ${filename:$(( ${#filename} - 1 )) } -1))
...

you don't need a for loop, you need a while loop, you should test for the existence [ -e $directory_name ] of the D3 value in the while loop, and if not decrement the value, as we don't have the...

D3 is the actual name? If not, what are the rules for this directory?
How many alpha bates? numbers? and upto which number you want check for the lower versions? like .. If not in D3, check D2, if...

thing i learned with scripting is that you can execute commands at prompt.
try to breakdown your code piece by piece and you'll see your output.
then change the syntax as desired.

if its too...

this means if you script get lower than 10 parameter then script echoes these
# ./script 1 2 3 4 5 6 # in this state , parameter count is 6 then return error messages..
# ./script 1 2 3 4 5 6...