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awk -v fname='japan usa uk' 'BEGIN {split(fname, a)}
{for(i = 1; i <= NF; i++)
{print $i > ("201005" a[i] ".txt")}}' alldata.dat

awk '
NR == FNR {a[FNR] = $0; n = FNR; next}
{ f = sprintf("output%02d.txt", ++c)
for(i = 1; i <= n; i++)
print a[i], $0 > f
close(f)
}' file1.txt file2.txt

This will work fine on many systems as long as there aren't too many lines in file2.txt. On other systems, you'll get a syntax error on the print statement. If there are a lot of lines in...

awk 'NR == FNR {a[FNR] = $0; n = FNR; next}
{c++;
for(i = 1; i <= n; i++)
{print a[i], $0 > "output" c ".txt"}}' file1.txt file2.txt

the condition is true if the specified file in variable exist...

We loop across the *.asc files, and figure out what the csv would be by stripping everything after the "_" and tacking .csv to the end... right?

Try this:


for asc in *.asc; do
...

That line creates an array (f1[]) of the values found in the 1st column ($1) of the 1st input file (when FNR {the line number in the of the input lines read from the current file} is equal to NR {the...

The for i in {1..3} works in some shells, but not others. Since the first line of your script doesn't specify what shell you want, it will run using your system's default shell. Then $i in your awk...

If you are using print, use OFMT='%.2f'.
awk -f interp.awk STEP=0.2 OFS="\t" OFMT='%.2f' data
Or, you may use printf.

Hi, it means "if the first field does not contain a letter" . [:alpha:] is a character class (http://pubs.opengroup.org/onlinepubs/009695399/basedefs/xbd_chap07.html#tag_07_03_01).

Try:

awk '
NR==FNR{
A[$1]=$2
if( $1!~/[[:alpha:]]/ ) {
if( min=="") min=max=$1
if( $1<min ) min=$1
if( $1>max ) max=$1
}
next
}
{
v=$1
...

$ cat interp.awk

(STEP=="") { STEP=1 } U {
D=(U<$1)?1:-1;
M=((V-$2)/(U-$1)) * D * STEP;

while( ((-D)*((U+=(D*STEP)) - $1)) > (STEP/2))
print U, V +=...

Your data doesn't seem to have a normal distribution.

There's a much more obvious way anyway, don't know why it didn't occur to me before :confused: Sort it, then look past the % number of lines...

= is assignment, == is comparison. This is true in both perl and awk.

awk 'NR==1 { print }' would print the first line and only the first line.

Ha, ha! Another classic example of changing requirements. Ok, here's some light:

if($. == 1) {print; next} ==> This part of the code checks if line in consideration is line #1 and if so prints the...

Try this...i don't think with xargs its achievable...

1>Write all the file names into a text file
ls *txt > temp
2>Execute this command to see what you really desired to see
perl -lne...

ls *txt | xargs -n6 paste

awk '$1<0{$0=0}1' input.txt
perl -lane 'if($_<0){print "0"}else{print $_}' input.txt

awk -F- '{$0=$1+0}1' infile

awk '$0+0<0{$0=0}1' inputfile

or

sed 's/^-.*/0/' inputfile

So you mean you have more than three files containing your data?

paste can handle lots of files. You'll have to be more specific, I don't see any good reason it wouldn't work for you yet.

Are you sure your output there is right? I get your numbers for the first, but your second appears to have an extra zero in the middle.

awk '{ A=0; V=0; for(N=1; N<=NF; N++) A+=$N ; A/=NF ;...

Another way..

awk '$0=($0<0)?$0+360:$0' file

awk '{ if ($1 < 0) $1 = $1 + 360; print; }' inputfile >outputfile