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Hopefully, RudiC's suggested awk script got you started down a workable path. Unfortunately, with an input file like:
pattern /* comment */
pattern2 /* start
continue comment
This >>> pattern...

Try thisawk ' {sub (/--.*$/,"")}
/\/\*/,/\*\// {next}
$0 ~ PAT {print FILENAME}
' PAT="insurance_no" file*
It removes comments first (assuming...

I bet it's a Solaris 10 system, because I get the exact messages using default awk.

Try /usr/xpg4/bin/awk or nawk

If it needs to be a sed command, try:sed -n '1h; 1!H; /FAILED/ {n;n;H;x;d}; /PASSED/ {n;H;x;p}' fileWorks on the sample you provided in post #1.

You can try something like this with awk:
awk '/PASSED/' RS=* ORS=**** file

grep ARGV /path/to/script.pl may give some indication but really the best way is to read and understand the script itself or failing that check any accompanying documentation

echo "this is a test1,this is test2,this is test3" | sed 's/[^,]*/="&"/g'

Try:
awk '{$1=$1}1' FS='\t' OFS='","' file
By assigning $1 onto itself, one of the fields gets altered and therefore the records gets recalculated and FS gets replaced by the OFS..





--...

Yes. If file1 has zero length, it takes file2 as file1 and has nothing left to work upon.
Tryawk 'FILENAME==ARGV[1] {T[$1$2$3]; next} ($2$3$4 in T) {next} 1' file1 file2

I'm not sure that this will run faster than what you tried before, but nevertheless give it a shot:awk 'NR==FNR {T[$1$2$3]; next} ($2$3$4 in T) {next} 1' file1 file2