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Hold buffer in sed

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# 1  
Old 02-05-2014
Hold buffer in sed
Hi Experts,

i have a file like below

Code:
****
table name is xyz
row count for previous day 10
row count for today 20
diff between previous and today 10
scan result PASSED
****
table name is abc
row count for previous day 90
row count for today 35
diff between previous and today 55
scan result FAILED
****
table name is def
row count for previous day 30
row count for today 10
diff between previous and today 20
scan result PASSED
****

My requirement is that i want to print block containing PASSED together like below output..

Code:
****
table name is xyz
row count for previous day 10
row count for today 20
diff between previous and today 10
scan result PASSED
****
table name is def
row count for previous day 30
row count for today 10
diff between previous and today 20
scan result PASSED
****

i tried like below but not getting proper result can you please help me in this?

Code:
sed -n '
'/PASSED/' !{ '/FAILED/'{
d
x
d
d
d
d
h
n
d
}
H
}
'/PASSED/' {
H
n
H
x
p
}' test_file

# 2  
Old 02-05-2014
You can try something like this with awk:
Code:
awk  '/PASSED/' RS=* ORS=**** file

This User Gave Thanks to Franklin52 For This Post:
Lakshman_Gupta
# 3  
Old 02-05-2014
If it needs to be a sed command, try:
Code:
sed -n '1h; 1!H; /FAILED/ {n;n;H;x;d}; /PASSED/ {n;H;x;p}' file

Works on the sample you provided in post #1.
This User Gave Thanks to RudiC For This Post:
Lakshman_Gupta
# 4  
Old 02-05-2014
Thats Great Rudic .. it worked !! I am not getting first portion of code just after sed -n and before /FAILED/ can you please explain?

Code:
 sed -n '
 1h
 1!H
 /FAILED/ {
 n
 n
 H
 x
 d
 }
 /PASSED/ {
 n
 H
 x
 p}' test_file

# 5  
Old 02-05-2014
It puts the first line to the hold buffer; all other lines will be appended... if you append the first line as well as the others, there will be an empty line at the beginning.
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