Search Results

Try:

printf -v num "%0.2f" $n

ksh93:
if (( 12.14>12.13 )); then echo greater; fi
bash:
if (( $(bc <<< "12.14>12.13") > 0 )); then echo greater; fi
posix:
if [ $(echo "12.14>12.13"|bc) -gt 0 ] ; then echo greater; fi

(g)awk

awk -F. 'length($2)==6{t++}END{print t}' file

nawk -F. '{if (length($2)==6) s++}END{print s}' myFile

Reformatting Scrutinizer's code and adding comments:
awk ' # invoke awk program and start script to be run by awk
/Output view:/ {# When an input line contains the string "Output...

One more lengthy way

may try

$ awk 'BEGIN{while(1){getline;if(/Output/){printf $0;break}x=x RS $0}print x}1' fileOR
$ awk '{if(/Output/)printf $0;else x=x RS $0}END{print x}' fileResulting...

And the backticks don't fit that definition?

Anything you can do in a script, you can do on the command line, anyway.

For the general solution, xargs is probably closest to what you have in...