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Try
awk '
{AL = index ($0, "<")
gsub (/<.?name>|^ */, _)
}
{printf "%s%s%s", AL==9?ORS:"", $0, AL==9?"\t":","
}
END {printf ORS
}
' file...

That file has DOS line terminators (<CR>, 0X0D). Get rid of them and it will fly.

This is a guess:
Your terminal output doesn't wrap and it is overwriting itself several times.

You could always test it by redirecting to a file instead of the screen.

Remove -q form first grep in pipe (-q causes no output and sets the return status so should only be used on last grep in chain):

ls -l "$file" | grep -q "$TIMEMATCH" | grep -q "^-" && echo $file

Unfortunately your options for date manulipitation under AIX 6.3 are limited.

I'd suggest using perl to convert entered date to epoch time and work with that.

#!/bin/ksh

printf "Enter...

How about array=( $(awk -F ' ' '{ print $NF }' log filename) )

Why are you trying to do this? Dynamic variable names are generally a terrible idea, and the usual things people want them for are often easily solved by other methods.

eval runs the evaluation twice
eval con=\$var$i
After the first evaluation this becomes e.g.
con=$var1

You can't directly expand a variable with a variable name. Here is a Korn shell script that provides four ways to do what you seem to be trying to do. Note that if the values you're assigning to...

The shell thinks you're performing a parameter expansion.

Try this:


con=var$i