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ksh : need to store the output of a awk command to a array

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# 1  
Old 10-08-2013
Lightbulb ksh : need to store the output of a awk command to a array
I have awk command :

Code:
 awk -F ' ' '{ print $NF }' log filename

And it gives the output as below:

Code:
06:00:00
parameters:
SDS
(2)
no
no
no
no

doc=4000000000).


information:
0
5898
5898
06:06:25

The problem is i need to save this in a array.

For example, when print or echo $array[0]
i should get 06:00:00 and similarly

Code:
$array[1] = parameters:
.
.
.
$array[n] = 06:06:25

my end goal is to print them using a print statement i.e

Code:
printf("start time: %d  and end time: %d", array[0], array[n]")

Output:

Code:
start time:06:00:00 and end time:06:06:25

Kindly help...
# 2  
Old 10-08-2013
How about
Code:
array=( $(awk -F ' ' '{ print $NF }' log filename) )

This User Gave Thanks to RudiC For This Post:
ramprabhum
# 3  
Old 10-08-2013
Lightbulb
Quote:
Originally Posted by RudiC
How about
Code:
array=( $(awk -F ' ' '{ print $NF }' log filename) )

I had tried this earlier but i was getting this error

Code:
ksh: 0403-057 Syntax error: `(' is not expected.

# 4  
Old 10-08-2013
A bit surprising. From this site's ksh(93) man pages:
Quote:
varname=(assign_list) No space is permitted between varname and the =. An assign_list can be one of the following: word ... Indexed array assignment.
What ksh version do you use?
# 5  
Old 10-08-2013
Lightbulb
Quote:
Originally Posted by RudiC
A bit surprising. From this site's ksh(93) man pages:

What ksh version do you use?
I use ksh88 version
# 6  
Old 10-10-2013
I can't help, then. Sorry.
# 7  
Old 10-10-2013
Code:
$ set -A arr parameters: 06:06:25
$ print ${arr[0]}
parameters:
$ print ${arr[1]}
06:06:25

So, if you want elements separated by white spaces:

Code:
set -f
set -A array $(awk '{ print $NF }' filename)
set +f

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