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You can just use sed....sed '/PATTERN/s/ to be changed/, YEHA! to be changed/' FILENAME

Not sure...
All I can see is that your "command" is the same... but does not the same so I would imagine a first script that formats for you (correct command and output) then to not call the correct...

system("ls -la"); You can't directly capture their output like backticks though, as far as I know. You might be able to redirect into a file then read the file after.

Use nawk or /usr/xpg4/bin/awk on Solaris.

Works for me :-/


[root@D152153 tmp]# awk 'NR==FNR\
{
a[++i]=$0;next
}
{
b[++j]=$0;
}
END\
{
for(k=1;k<=j;k++)
{
print "COMMAND " a[k] " COMMAND_OPTION " b[k]
}...

s/.../.../

the & refer to what has previously been matched in the whole pattern space (here within the first /.../ )

This example would put the third column at the firt column:...

SCRIPTS>awk -F"," '{print $1,$2,(($3-$4)>0?$3-$4:$3)}' OFS="," input_file

Please, first verify if you do not have in your input file the octal 251 which is ©.

If you do, then choose another special character that is not in your file.

#!/usr/bin/ksh
typeset -i mLen...

cat input.txt | awk '{
if (length($0)+length(APPEND) < 20 ){
TMP = APPEND $0
gsub(/\\/,"",TMP)
print TMP
APPEND=""
}else{

TMP = APPEND $0
gsub(/\\/,"",TMP)
LINE = substr(TMP,1,19)...

See if this works for you:
#!/usr/bin/ksh
typeset -i mLen
mPrevLine=''
sed 's/\\//' Inp_File | while read mLine
do
mLine2=${mPrevLine}${mLine}
mLen=${#mLine2}
if [[ ${mLen} -ge 20 ]];...

sed 's/\/$//g' inputfile | awk '{ORS="";print}'|xargs| sed 's/\/$//g'

Let's try with perl.
perl -ne 'chop $_;printf $_; END {printf "\n";}' input.txt

Lets try with:
echo "abc/de/fg/
12/3/4/5/67/
morestuff/" | sed 's/\/$//' | tr -d "\n"
abc/de/fg12/3/4/5/67morestuffRegards

xargs -n1 | displays 1 string per line
sed '/\//!d' | will delete every lines that do NOT contain a slash (the negation "NOT" is specified by the bang"!")

What system are you using? It works for me on Solaris and Linux.

-n means do not print lines unless instructed to.
{} groups commands together
N reads another line
p prints

awk '/\/folder1\/folder2\/folder3\//{print$2}' get_info_file >/tmp/grepoutputor nawk on solaris
nawk '/\/folder1\/folder2\/folder3\//{print$2}' get_info_file >/tmp/grepoutput

@panyam
I had a try - thanks for the fast response
using:
grep "/folder1/folder2/folder3/" rem | cut -d" " -f2 INPUTFILE


It suppose to be:


grep "/folder1/folder2/folder3/"...

grep "/folder1/folder2/folder3/" INPUTFILE| cut -d" " -f2

Assuming that $(BUILDPATH) is a command that returns a string. You need to take a look at what your shell needs concerning quotation and shell variables in sed.
Highlighting some points you should...