Search Results

Try:
ls | sort -nt_ -k3,3 -k2,2

Actually "&" told to shell to do this process in background,
If u want to look this process use following command.

fg 1

If u want to send this back to background use following command.
...

To run it in the background, so you can do other things while it's zipping.

And here is another way:

#!/bin/ksh
oIFS="$IFS"; IFS=, ; set -- $1 ; IFS="$oIFS"
for i in "$@"; do
echo name = $i
done
echo Total Names: $#

$>./test Cooper,"Billy Bob",Trevor,Smithers...

Not test, just give the clue for you.


find Parent -type f > filelist.log
for i in `cat filelist.log`
do
DIR=`dirname $i`
FILENAME=`basename $i`
mkdir -p $DIR/subdir2
cp $i...

Julian date for '20000101' = 2451545
Julian date for '22000101' = 2524594

That is more than 73000 days.
to check to see if all dates are there try:

wc -l unique.txt


To see if the date...

Check man page or usage document of the command. It should have option to output the code only (in fact, it should be the default). If not, the person who wrote the program doesn't understand Unix....