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Try:sed 's/^/XYZ|/' file

Hello,

Could you please try the following command for same.


awk '{print "XYZ|"}'1 ORS="" filename


It will show output as follows.


XYZ|12||34|56|78



Thanks,
R. Singh

awk -F '|' ' $3 =="Y" && $4=="0" && $6=="N" {var1++}
$3 =="Y" && $6=="N" {var2++}
{next}
END{print "condition 1", var1, " condition2", var2}'...

The exclusive stuff with next inawk -F '|' '
$3 =="Y" && $4=="0" && $6=="N" {var1++}
$3 =="Y" && $6=="N" {var2++}
END {
print "condition1", var1+0
print "condition2", var2+0
}
'...

Like this?
awk -F"|" '{
if ($3=="Y" && $4==0 && $6=="N")
variable1++
if ($3 =="Y" && $6=="N")
variable2++
}
END {print "variable1=" variable1 "\nvariable2=" variable2}' inputfil

not tested


nawk -F"," ' /^3/ {
{
if(index($13,"-") > 0)
{
$13=substr($13,2,length($0))"-"
}
print($13,"5",$1,$28,"$27",$26)
}' $FILENAME >> New_file

awk '{print $0<0?-$0"-":$0}' inputfile

Yes. I'd start you off w a hint such as: %035.35s.

However, the most effective approach for you overall is to scrounge up a tutorial that covers printf. Really the same features and behavior...

Try: printf "%015.2f%c%015.2f\n" $v1 $v3 $v2

different shell and OS, but...you're just mixing metaphors with the printf formatting directions. %d is decimal, where you inputs are float...%f. The +-char needs to be treated as a string, and...

Use printf "%.2f",credit in the END section.

When specifying multiple variables, you need to put -v in front of each of them:nawk -v FD="$F_D" -v SS="$S_S" -v DS="$D_S" 'BEGIN {FS=","} {printf("%-1s%-4s%-30s","0",$2,FD,SS,DS)}'

1) Add -v options nawk -v FD="$F_D" -v SS="$S_S" -v DS="$D_S" 'BEGIN {FS=","} {printf("%-1s%-4s%-30s","0",$2,FD,SS,DS)}'

2) Remove loop (cat,grep while read) :nawk -v FD="$F_D" -v SS="$S_S" -v...

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