Problem with printf in UNIX KSH shell

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# 1  
Old 07-10-2011
Problem with printf in UNIX KSH shell


I am using
SunOS 5.9 and KSH(bin/ksh)

The problem am facing is

error message diaplyed on screen

printf: 12099415.79 not completely converted
printf: + expected numeric value
printf: 11898578.29 not completely converted

When i try printing with
printf ("%-9d%-1d%-9d" $v1 $v3 $v2)
The output is 120994150 18985780 which is not expected !

my requirement of O/P is 000012099415.79+000011898578.29

var1 and var 2 with left padded with zeros to make it 15(including decimal and 2 places after that)

Yes i am confused with printf, so please let me know what exact formatting i should use to get the desired output...
# 2  
Old 07-10-2011
printf "%015.2f%c%015.2f\n" $v1 $v3 $v2

This User Gave Thanks to bartus11 For This Post:
# 3  
Old 07-10-2011
different shell and OS,'re just mixing metaphors with the printf formatting directions. %d is decimal, where you inputs are float...%f. The +-char needs to be treated as a string, and therefore you'd use %s:

~ # printf "%-9d %-1d %-9d\n" 12.79 '+' 11.79                                   
sh: invalid number '12.79'                                                      
0         sh: invalid number '+'                                                
0 sh: invalid number '11.79'                                                    
~ # printf "%-9f %-1s %-9f\n" 12.79 '+' 11.79                                   
12.790000 + 11.790000

When you'd started talking about zero-padding can play with the following and see what you'd need:

~ # printf "%017.2f %-1s %017.2f\n" 12.79 + 11.79                               
00000000000012.79 + 00000000000011.79

This User Gave Thanks to curleb For This Post:
# 4  
Old 07-11-2011
Thank you all...
One more question..
will it be possible to use the same printf formatting inside nawk ??
# 5  
Old 07-11-2011
Absolutely, only you need to separate the args with commas; slight difference in the syntax between ksh and (|n|g)awk...
# 6  
Old 07-11-2011

printing spaces, gives me a problem,but i figured a way out is that legitimate ?
This is how am printing using printf in UNIX

printf "%-1s%-2s%-4s%-30s%-15s%-12s%-15s              %015.2f%c%015.2f%c%c   %-3s         %-1c\n" "0" $H1 $H2 $F_D $S_S $D_P $S_P $CT $P $DT $M $W $CMP "X" >> New

Output is also as expected
cat New
0122010KKPHARMA_KKE                  KKE_BRIDGE     COMPETRED   CMPPP-GL                     000012099415.79+000011898578.29-W   140         X

But is there a way to print spaces with harding inside a variable like

SP=" "
and use the above SP in printf ?

Ofcourse the $F_D="KKPHARMA_KKE " works absolutly fine but not SP=" "

How do i print aplha numeric characters with zeros padded in front? is it possible? using printf !Smilie
# 7  
Old 07-11-2011
Yes. I'd start you off w a hint such as: %035.35s.

However, the most effective approach for you overall is to scrounge up a tutorial that covers printf. Really the same features and behavior throughout pretty much all languages, shells, environments but mostly syntactic nuances to watch out for.
This User Gave Thanks to curleb For This Post:
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